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matrenka [14]
3 years ago
11

The image below shows a jar containing four different liquids, each a different color. The liquids do not mix, so the colors rem

ain separate. Which of the following statements are true? Check all that apply.
A. Blue is more dense than clear.
B. Because it fell to the bottom, red is the most dense.
C. Clear is the most dense.
D. Clear is more dense than yellow, but less dense than red or blue.

Physics
1 answer:
Reika [66]3 years ago
8 0

<u>Answer:</u>


<u>Density</u> is a characteristic property of a substance or material and is defined as the relationship between the mass and volume of a specific substance or material.

Each liquid has its own density, and according to this the liquid will float or fall to the bottom.  

If two liquids of different densities are poured in a container, the liquid with lower density will float and the liquid with more density will fall to the bottom.

In other words, <u>liquids with low density will float over the liquid with more density  </u>

In the bottle of this experiment the red liquid is the most dense and falls to the bottom, then the liquids with lower density will float on it, being the yellow liquid the less dense.


<h2>Therefore, the true statements here are A, B an D. </h2>
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Answer:

A) reduced air pressure on the ball.

Explanation:

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A ball hits a wall horizontally at 6m/s and rebounces at 4.4m/s the ball is in contact with wall for 0.04 sec. what is the accel
Svetlanka [38]

Answer:

Acceleration (a) = 40 m/s²

Explanation:

Given:

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Computation:

We know that,

⇒ v = u + at

⇒ a = (v - u) / t

⇒ Acceleration (a) = (4.4 - 6) / 0.04

⇒ Acceleration (a) = (-1.6) / 0.04

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8 0
3 years ago
A river flows at 2m/s. The velocity of a ferry relative to the shore is 4m /s at right angle to the current. What is the velocit
monitta

The velocity of the ferry relative to the current is 4.5 m/s.

<h3>Relative velocity</h3>
  • Relative velocity is the velocity of a body as observed from the reference point of another body either stationary or in motion.

Since the river is flowing parallel to the shore and the ferry is moving perpendicular to the shore, their velocities are at right angles to each other.

The two velocities form a right angled-triangle of sides 2, 4 and a hypotenuse which gives the relative velocity of the ferry to the current.

Using Pythagoras rule:

  • c² = a² + b²
  • Let c be the hypotenuse
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c² = 4² + 2²

c² = 16 + 4

c = 20

c = √20

c = 4.47 m/s

c ≈ 4.5 m/s

Therefore, the velocity of the ferry relative to the current is 4.5 m/s.

Learn more about relative velocity and Pythagoras rule at: brainly.com/question/25617868

5 0
3 years ago
A heavy rope, 80 ft long and weighing 32 lbs, hangs over the edge of a building 100 ft high. how much work w is done in pulling
allochka39001 [22]
The first thing you should know for this case is that work is defined as the product of force by the distance traveled in the direction of force.
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 W = Fd
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 W = ∫F (x) dx
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6 0
3 years ago
Fiber-optic cables are used widely for internet wiring, data transmission, and surgeries. When light passes through a fiber-opti
Gwar [14]
After one meter, 3.4% of the light is gone ... either soaked up in the fiber
material or escaped from it.  So only  (100 - 3.4) = 96.6% of the light
remains, to go on to the next meter.

After the second meter,  96.6%  of what entered it emerges from it, and
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of the fiber.

==>  After 2 meters, the intensity has dwindled to  (0.966)² of its original level.
It's that exponent of ' 2 ' that corresponds to the number of meters that the light
has traveled through.

==>  After  'x'  meters of fiber, the remaininglight intensity is (0.966) ^x-power
of its original value.

If you shine 1,500 lumens into the front of the fiber, then after 'x' meters of
cable, you'll have
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lumens of light remaining.
 
=========================================

The genius engineers in the fiber design industry would not handle it this way.
When they look up the 'attenuation' of the cable in the fiber manufacturer's
catalog, it would say  "15dB per 100 meters".

What does that mean ?    Break it down:  15dB in 100 meters is <u>0.15dB per meter</u>.
Now, watch this:

Up at the top, the problem told us that the loss in 1 meter is  3.4% .  We applied
super high mathematics to that and calculated that  96.6% remains, or  0.966.

Look at this  ==>      10 log(0.966) =  <em><u>-0.15</u>  </em>  <==  loss per meter, in dB .

Armed with this information, the engineer ... calculating the loss in  'x'  meters of
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--  0.15 dB loss per meter

--  'x' meters of cable

--  0.15x dB of loss.

If  'x' happens to be, say,  72 meters, then the loss is  (72) (0.15) = 10.8 dB .

and  10 ^ (-10.8/10) = 10 ^ -1.08 = 0.083  =  <em>8.3%</em>  <== <u>That's</u> how much light
he'll have left after 72 meters, and all he had to do was a simple multiplication.

Sorry. Didn't mean to ramble on. But I do stuff like this every day.
5 0
3 years ago
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