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arlik [135]
3 years ago
7

Two propane-butane mixtures are contained in separate containers. The first mixture contains 30 wt% propane, and the second cont

ains 60 wt% propane. If 1,000 g of the first mixture is combined with 1,200 g of the second, what are the mass and compositions of the product?
Chemistry
1 answer:
ohaa [14]3 years ago
5 0

Answer:

750 grams is the mass of product and 34.09% is the compositions of the product.

Explanation:

Container 1 , 30% of propane by mass:

Container 2 , 60% of propane by mass:

Mass of mixture in container-1 = 1000 g

Mass of propane in 1000 g of mixture = m

m= \frac{30}{100}\times 1000 g= 300g

Mass of mixture in container-2 = 1200 g

Mass of propane in 1200 g of mixture = m'

m'= \frac{60}{100}\times 1200 g= 720 g

After mixing 1000 grams and 1200 grams of mixture

Final mass of mixtures = 1000 g + 1200 g = 2200 g

Final mass of propane = 300 g+ 720 g = 750 g

Composition of propane after mixing of mixtures :

\%=\frac{750 g}{2200 g}\times 100=34.09\%

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The question is incomplete, the complete question is;

A student prepared several aqueous sodium chloride (NaCl) solutions to observe boiling point elevation at various molal concentrations, however, several errors were made throughout the procedure. Determine whether these errors would cause the observed boiling point to be increased or decreased relative to the expected boiling point, based on the procedure, or have no effect on the experimental results.

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If the flask is washed but not dried, then the solution will be further diluted than expected. As a result of this further dilution, the observed boiling point will be less than the expected boiling point because the boiling point depends on the solution's concentration.

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