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arlik [135]
2 years ago
7

Two propane-butane mixtures are contained in separate containers. The first mixture contains 30 wt% propane, and the second cont

ains 60 wt% propane. If 1,000 g of the first mixture is combined with 1,200 g of the second, what are the mass and compositions of the product?
Chemistry
1 answer:
ohaa [14]2 years ago
5 0

Answer:

750 grams is the mass of product and 34.09% is the compositions of the product.

Explanation:

Container 1 , 30% of propane by mass:

Container 2 , 60% of propane by mass:

Mass of mixture in container-1 = 1000 g

Mass of propane in 1000 g of mixture = m

m= \frac{30}{100}\times 1000 g= 300g

Mass of mixture in container-2 = 1200 g

Mass of propane in 1200 g of mixture = m'

m'= \frac{60}{100}\times 1200 g= 720 g

After mixing 1000 grams and 1200 grams of mixture

Final mass of mixtures = 1000 g + 1200 g = 2200 g

Final mass of propane = 300 g+ 720 g = 750 g

Composition of propane after mixing of mixtures :

\%=\frac{750 g}{2200 g}\times 100=34.09\%

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How much water (H2O ) would form if 4.04 g of hydrogen (H2) reacted with 31.98 g of oxygen (O2 )?
Norma-Jean [14]

Answer:

Mass = 36 g

Explanation:

Given data:

Mass of water formed = ?

Mass of hydrogen = 4.04 g

Mass of oxygen = 31.98 g

Solution:

Chemical equation:

2H₂ + O₂   →   2H₂O

Number of moles of hydrogen:

Number of moles = mass/molar mass

Number of moles = 4.04 g/ 2 g/mol

Number of moles = 2.02 mol

Number of moles of oxygen:

Number of moles = mass/molar mass

Number of moles = 31.98 g/ 32 g/mol

Number of moles = 1.0 mol

Now we will compare the moles of water with hydrogen and oxygen.

                O₂         :         H₂O

                 1           :           2

                H₂         :         H₂O

                 2          :          2

               2.02       :      2.02

Number of moles of water formed by oxygen are less thus oxygen will limiting reactant.

Mass of water:

Mass = number of moles × molar mass

Mass = 2 mol × 18 g/mol

Mass = 36 g

8 0
2 years ago
If the pH of vinegar is 3.0, what is the concentration of H+ in vinegar?
Cerrena [4.2K]

Answer: The concentration of H^{+} ions in vinegar is 0.001 M.

Explanation:

Given: pH = 3.0

pH is the negative logarithm of concentration of hydrogen ion.

The expression for pH is as follows.

pH = - log [H^{+}]

Substitute the value into above expression as follows.

pH = - log [H^{+}]\\3.0 = - log [H^{+}]\\conc. of H^{+} = antilog (- 3.0)\\= 0.001 M

Thus, we can conclude that the concentration of H^{+} ions in vinegar is 0.001 M.

5 0
2 years ago
How many atoms of hydrogen are found in the compound, NH4C2H302?
Mariulka [41]
<h2>Answer:</h2>

7 hydrogen atoms

<h2>Explanation:</h2>

N<em><u>H4</u></em>C2<em><u>H3</u></em>02

In this problem we see the hydrogen atom twice, along with the numbers 4 and 3 next to them. (as shown above in bold & underlined)

So, in order to find how many there are in all you add both hydrogen atoms together-

H4+H3= H7

therefore, there are 7 hydrogen atoms in all

8 0
2 years ago
Within the main group of elements, what do elements in a family have in common?
statuscvo [17]
They have same chemical properties
for example the elements of group VIII are called noble gases .They are unreactive, odorless and colorless.
8 0
2 years ago
If Marie and Calvin dissolve 50 grams of KBr in 100 grams of water at 90oC, the solution is
hram777 [196]

Answer:

The solution is 50 %wt

Explanation:

50% wt is a sort of concentration and means, that 50 g of solute (in this case, the potassium bromide) dissolved in 100 g of water.

It is the same to say, that there are 50g of KBr for every 100g of H₂O

8 0
3 years ago
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