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3 years ago

The Ph scale is logarithmic; how many times stronger is a Ph of 4 versus a Ph of 2?

Chemistry

1 answer:

Molodets [167]3 years ago

6 0

Answer:

A pH greater than 7 is basic. The pH scale is logarithmic and as a result, each whole pH value below 7 is ten times more acidic than the next higher value. For example, pH 4 is ten times more acidic than pH 5 and 100 times (10 times 10) more acidic than pH 6.

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A balloon vendor at a street fair is using a tank of helium to fill her balloons. The tank has a volume of 113.0 L and a pressur

lisov135 [29]

Given Data:
P₁ = 122 atm

P₂ = 112 atm

V₁ = 113 L

V₂ = ?

Solution:
Let suppose the gas is acting ideally. According to Ideal gas equation, keeping the temperature constant,

P₁ V₁ = P₂ V₂
Solving for V₂,
V₂ = P₁ V₁ / P₂
Putting Values,
V₂ = (122 atm × 113 L) ÷ 112 atm

V₂ = 113 L

Converting Volume to Moles,
As,
22.4 L is occupied by = 1 mole of He gas
So,
113 L will occupy = X moles of He gas

Solving for X,
X = (113 L × 1 mole) ÷ 22.4 L

X = 5.04 Moles of He

7 0

4 years ago

Yoooo help me w this one

Scilla [17]

Answer:

0.84kg of gatorade powder

Explanation:

From the question given, we were told that 0.6kg of gatorade powder required 5 gallons of water.

To obtain the mass of gatorade needed for 7 gallons of water, we simply do the following:

0.6kg of gatorade powder required 5 gallons of water.

Therefore, xkg of gatorade powder will require 7 gallons of water i.e

xkg of gatorade powder = (0.6 x 7)/5

xkg of gatorade powder = 0.84kg

Therefore, 0.84kg of gatorade powder will be required.

6 0

3 years ago

Im doing a naming assignment and was couldnt find NpO3

scoray [572]

Answer:me to

Explanation:

5 0

3 years ago

How many inches is in 10 cm? Use dimensional analysis to show your work. Include the work in your answer.

Mumz [18]

Answer:

To get the answer divide 10cm by 2.54

Explanation:

$\frac{10}{2.54} \\ = 10 \div \frac{254}{100} \\ = 10 \times \frac{100}{254} \\ = \frac{1000}{254} = 3.937inches$

Hope this helps

6 0

3 years ago

The natural distribution of the isotopes of a hypothetical element is 60.795% at a mass of 281.99481 u, 22.122% at a mass of 283

fenix001 [56]

Answer: The average atomic mass of the element is 283.291 amu

Explanation:

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$ .....(1)

For isotope 1:

Mass of isotope 1 = 281.99481 amu

Percentage abundance of isotope 1 = 60.795 %

Fractional abundance of isotope 1 = 0.60795

For isotope 2:

Mass of isotope 2 = 283.99570 amu

Percentage abundance of isotope 2 = 22.122 %

Fractional abundance of isotope 2 = 0.22122

For isotope 3:

Mass of isotope 3 = 286.99423 amu

Percentage abundance of isotope 3 = [100 - (60.795 + 22.122)] = 17.083 %

Fractional abundance of isotope 1 = 0.17083

Putting values in equation 1, we get:

$\text{Average atomic mass of element}=[(281.99481\times 0.60795)+(283.99570\times 0.22122)+(286.99423\times 0.17083)]\\\\\text{Average atomic mass of element}=283.291amu$

Hence, the average atomic mass of the element is 283.291 amu

5 0

4 years ago