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goblinko [34]
4 years ago
15

What do the words fit, set, and read have in common?

Chemistry
1 answer:
Zigmanuir [339]4 years ago
7 0
<span>They keep the same form no matter what tense is used.
</span>
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Ethyl iodide (C2H5I) decomposes at a certain temperature in the gas phase as follows: C2H5I(g) → C2H4(g) + HI(g) From the follow
lutik1710 [3]

Answer:

Zero order

Explanation:

Looking at the data we can note a linear dependence between concentration and time.  

Time   Conc.

0          2

15         1.82

30        1.64

48        1.42

75        1.10

In the first 15 min it was consumed 2-1.82=0.18. So the rate is r=\frac{\Delta C}{\Delta t} = \frac{0.18}{15}=0.012

From 15 to 30 min (it has passed 15 min) is consumed 1.82-1.64=0.18, so as in the previous calculation the rate is r=0.012.

From 30 to 48  (it has passed 18 min)the rate is r= \frac{0.22}{18}\approx 0.012  

From 48 to 75  (it has passed 27 min) the rate is r= \frac{0.32}{27}\approx 0.012  

So these results suggest that despite of the ever minor concentration of the reactant the rate is ever the same. Hence the reaction rate could be expressed as r= k^{0} = 0.012 mol L^{-1} min^{-1} that is, the reaction is the zero order respect to C2H5I since it is not depending on concentration of C2H5I.  

7 0
3 years ago
How many kilocalories are required to increase the temperature of 15.6 g of iron from 122 °c to 355 °c. the specific heat of iro
Dmitriy789 [7]

Heat require to boil 15.6 g iron from 122 C0to 355 C0 whereas,

Q = m s dT

Where, m is mass of iron

s is specific heat of iron

d T is change in temperature in celcius

= 15.6 g * 0.45 J /g /C * (355 - 122)  = 1.63 * 10^3 J

If  

1 cal = 4.2 J

Then,  

Q = (1.63 * 10^3) /4.2 = 0.389 K cal

Thus 0.389 k cal of enrgy  is required by a 15.6 g Fe to reach to 355 C^0

4 0
4 years ago
PLEASE HELP ME &amp; will mark the brainliest!
AfilCa [17]

Answer:

HCOOH(aq) + OH-(aq) —> HCOO-(aq) + H2O(l)

Explanation:

HCOOH is a weak acid and so will not ionised completely in solution.

KOH is a strong base and will ionised completely as shown below

KOH(aq) –> K+(aq) + OH-(aq)

The overall reaction can be written as follow:

HCOOH(aq) + K+(aq) + OH-(aq) —> HCOO-(aq) + K+(aq) + H2O(l)

Cancel out the K+ to obtain the net ionic equation as shown below

HCOOH(aq) + OH-(aq) —> HCOO-(aq) + H2O(l)

3 0
4 years ago
Using the equation 2H2+O2 = 2H2I, if 192 g if oxygen reacts completely, how many grams of hydrogen must react with it
dimaraw [331]
I assume there is a typo in the equation.  It is H2O instead of H2I.

The ratio of H2 and O2 that react with each other is 2:1.  To find out the grams of H2, we need to first find out the moles of O2 and H2.

Moles of O2 = mass of O2/molar mass of O2 = 192g/32g/mol = 6 mol.  Therefore, the moles of H2 = 6mol *2 = 12 mol.

So the mass of H2 that reacts with O2 = moles of H2 * molar mass of H2 = 12 mol * 2 g/mol = 24 g

7 0
4 years ago
Science question:<br> Could you have seasons without<br> revolution? Why or why not?
marusya05 [52]

Answer:

No

Explanation:

The Earth would not have seasons if there is no revolution because the temperatures would not change.

4 0
3 years ago
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