Answer:
100°C
Explanation:
The following were obtained from the question:
Initial temperature (T1) = 298 K
Initial pressure (P1) = 32.5 Psi
Final pressure (P2) = 40.68 Psi
Final temperature (T2) =..?
The final temperature can be obtained as follow:
P1/T1 = P2/T2
32.5/298 = 40.68/T2
Cross multiply to express in linear form
32.5 x T2 = 298 x 40.68
Divide both side by 32.5
T2 = (298 x 40.68) /32.5
T2 = 373K
Next, we shall convert 373K to celsius.
This is illustrated below:
T(°C) = T(K) – 273
T(K) = 373
T(°C) = 373 – 273
T(°C) = 100°C
Therefore, the temperature of the air inside the tire at 40.68 Psi is 100°C
Answer:
An aqueous solution of 
will be an acid and have a pH of less than 7.
An aqueous solution of 
will be a neutral solution and have a pH equal to 7.
An aqueous solution of 
will be an base and have a pH of more than 7.
Explanation:
pH is defined as the negative logarithm of the concentration of hydrogen ions.
Thus,
pH = - log [H⁺]
pH scale generally runs from 1 to 14 where pH = 7 represents neutral medium, pH < 7 represents acidic medium and pH > 7 represents basic medium.
Thus,
<u>An aqueous solution of will be an acid and have a pH of less than 7.</u>
<u>An aqueous solution of will be a neutral solution and have a pH equal to 7.</u>
<u>An aqueous solution of will be an base and have a pH of more than 7.</u>
Answer:
65
Explanation:
100-35=65 es demasiado facil
Answer: H2O (water)
Explanation:
The answer choices for this question are:
A) H2O
B) N2
C) SO2
D) NO3
E) Cl2
The solution of the problem is:
1) Data:
<span> density, d = 1.4975 g/liter
volume, V = 8.64 liter
pressure, p = 2.384 atm
temperature, T = 349.6 K
2) Formulas:
d = m/V => m = d*V
n = m / molar mass => molar mass = m / n
pV = nRT => n = pV / RT
3) Solution
n = pV / RT = 2.384 atm * 8.64 liter / (0.0821 atm*liter/K*mol * 349.6K)
n = 0.7176 moles
</span>m = dV = 1.4975 g/ liter * <span>8.64 liter = 12.9384 g
molar mass = m / n = 12.9384 g / 0.7176 moles = 18.03 g/mol
That molar mass corresponds to the molar mass of water, therefore the gas is H2O (water vapor).</span>
The answer for your question is D
