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inysia [295]
3 years ago
15

a ball at the end of a string is whirled in a horizontal circle. if it takes 2 seconds to make a revolution and the strong lengt

h is 2 m , how fast is the ball moving ? How much is it being accelerated
Physics
1 answer:
Taya2010 [7]3 years ago
8 0

You can calculate the speed of the ball by the distance it travels divided by the time.

Length of string = 2m

Circumference of circle = 2*radius*π = 4*pi = ~12.6 meters

Speed = distance/time = 12.6m/2s = 6.28m/s

Acceleration = V²/R where the velocity at any one point is the same as the speed.

acceleration = (6.28)²/2 = ~19.72m/s²

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A scientist records the motion of an object. She writes down that the
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3 years ago
A large in-falling fragment could be tracked using radar. Explain how distance, speed, and the direction of motion, of the fragm
ch4aika [34]

Answer:

speed, distance  and direction of motion of the object can be determined by analyzing the radio wave.

Explanation:

We know that radar operates by transmitting radio waves to a destination and these waves are comes back to the receiver station. By Considering this transmission and receiver process, we can measure the distance, velocity and path of an object's movement.

Distance can be assessed by taking following consideration,  the velocity of the waves is V. It can help to assess the time made for the waves to be emitted by the radar and felt by the receiver, let the time be t.

Therefore  distance can be determine as D= v*t/2,

here 2 signifies that the distance travelled by the wave in either direction ( from transmitter to receiver and vice verse)

Using the source wave frequency, speed can be computed. In a specific frequency, the radar starts sending out the frequencies and the reflected wave will have a distinct frequency. The velocity can be determine by

v= (\Delta f/f)(c/2),

where\Delta fis the change in frequency and

c is the speed of light (the wave).

Direction can be determine by applying above principle. change in frequency is used to determine the direction in the following way:

When the frequency transition is very low, the object moves away from the radar and vice verse.

3 0
3 years ago
Two identical conducting spheres are placed 80.0 cm apart. One is given a charge of 5.8 C and the other is given a charge of 6.4
Zepler [3.9K]

Answer: 5.214(10)^{11} N

Explanation:

According to <u>Coulomb's Law:</u>  

<em>"The electrostatic force F_{E} between two point charges q_{1} and q_{2} is proportional to the product of the charges and inversely proportional to the square of the distance d that separates them, and has the direction of the line that joins them".</em>

<em />

Mathematically this law is written as:

F_{E}=K\frac{q_{1}.q_{2}}{d^{2}}  

Where:

F_{E}  is the electrostatic force

K=8.99(10)^{9} Nm^{2}/C^{2} is the Coulomb's constant  

q_{1}=5.8 C and q_{2}=6.4 C are the electric charges

d=80 cm \frac{1 m}{100 cm}=0.8 m is the separation distance between the charges

Solving:

F_{E}=8.99(10)^{9} Nm^{2}/C^{2}\frac{(5.8 C)(6.4 C)}{(0.8 m)^{2}}  

F_{E}=5.214(10)^{11} N    

7 0
3 years ago
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