Question

Check My Work (1 remaining) Boron coated with SiC (or Borsic) reinforced aluminum containing aligned 20 vol% fibers is an important high-temperature, lightweight composite material. Estimate the modulus of elasticity perpendicular to the fibers. The modulus of elasticity of the fibers is 55 X 106 psi and the modulus of elasticity of aluminum is 10 X 106 psi.

Answer 1

Answer:

$E = 12 * 10^{6} Psi$

Explanation:

Modulus of Elasticity perpendicular to the fibre,

$\frac{1}{E} = \frac{B_{B} }{E_{B} } + \frac{B_{Al} }{E_{Al} }$

$B_{B} = 20% = 0.2$

$B_{Al} = 80% = 0.8$

$E_{B} =55 * 10^{6} Psi$

$E_{Al} =10 * 10^{6} Psi$

$\frac{1}{E} = \frac{0.2 }{55 * 10^{6} } + \frac{0.8 }{10 *10^{6} }$

$\frac{1}{E} = 8.36 * 10^{-8} \\E = \frac{1}{8.36 * 10^{-8} }\\E = 12 * 10^{6} Psi$