Answer:
Centrifugal force
Explanation:
The reacting force that is equal to and opposite in the direction to the centripetal force and tends to fling air out of the center of rotation of High and Low pressure systems is called centrifugal force.
Centrifugal force is force that causes an object moving in a circular path to move out and away from the center of it's path, it always centripetal force and the force is imaginary, which can only be felt and not seen.
Responder:
13,01 m / s
Explicación:
Paso uno:
datos dados
masa de la persona 1 m = 80 kg
velocidad de la persona 1 v = 9 m / s
masa de la persona 2 M = 55kg
velocidad de la persona 2 v =?
Segundo paso:
la expresión del impulso se da como
P = mv
para la primera persona, el impulso es
P = 80 * 9
P = 720N
Paso tres:
queremos que la segunda persona tenga el mismo impulso que la primera, por lo que la velocidad debe ser
720 = 55v
v = 720/55
v = 13,09
v = 13,01 m / s
Por lo tanto, la magnitud de la velocidad debe ser 13.01 m / s.
vf ^2 = kx^2/m = 56(0.75)^2 / 2.5 = 12.6
Therefore, v= 3.5 m/s.
Answer:
The force of friction acting on block B is approximately 26.7N. Note: this result does not match any value from your multiple choice list. Please see comment at the end of this answer.
Explanation:
The acting force F=75N pushes block A into acceleration to the left. Through a kinetic friction force, block B also accelerates to the left, however, the maximum of the friction force (which is unknown) makes block B accelerate by 0.5 m/s^2 slower than the block A, hence appearing it to accelerate with 0.5 m/s^2 to the right relative to the block A.
To solve this problem, start with setting up the net force equations for both block A and B:

where forces acting to the left are positive and those acting to the right are negative. The friction force F_fr in the first equation is due to A acting on B and in the second equation due to B acting on A. They are opposite in direction but have the same magnitude (Newton's third law). We also know that B accelerates 0.5 slower than A:

Now we can solve the system of 3 equations for a_A, a_B and finally for F_fr:

The force of friction acting on block B is approximately 26.7N.
This answer has been verified by multiple people and is correct for the provided values in your question. I recommend double-checking the text of your question for any typos and letting us know in the comments section.