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Hoochie [10]
3 years ago
15

Which statement best describes the difference between acceleration and velocity?

Physics
1 answer:
Sloan [31]3 years ago
8 0
C. is the answer because acceleration is the change in velocity in time while velocity is speed with a direction
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A commercial jet liner takes off with an average acceleration of 3 g. How long does it take to reach the end of its runway which
ANEK [815]

Answer:

The time taken for the commercial Jet liner to reach the end of its runway is 10.18 s.

Explanation:

Given;

average acceleration of the commercial Jet liner, a = 3g = 3 x 9.8 m/s² = 29.4 m/s²

distance traveled by the commercial Jet liner, s = 1542 m

The time taken for the commercial Jet liner to reach the end of its runway is calculated as follows;

s = ut + ¹/₂at²

where;

u is the initial velocity of the commercial Jet liner = 0

s = 0 + ¹/₂at²

s = ¹/₂at²

2s = at²

t = \sqrt{\frac{2s}{a} } \\\\t = \sqrt{\frac{2 \times 1524}{29.4} } \\\\t = 10.18 \ s

Therefore, the time taken for the commercial Jet liner to reach the end of its runway is 10.18 s.

6 0
3 years ago
Block A, with a mass of 4 kg, is moving with a speed of 2 m/s while Block B, with a mass of 8.4 kg, is moving in the opposite di
dybincka [34]

Answer:

The center of mass move with the velocity of -3.487 m/s.

Explanation:

Given values of block A.

Mass of block A, (M1) = 4 kg

Speed of block A, (V1) = 2 m/s

Given values of block B.

 Mass of block B, (M2) = 8.4 kg

Speed of block B, (V2) = -6.1 m/s

Below is the formula to find the velocity of center of mass.

Velocity = \frac{M1V1 + M2V2}{M1 + M2} \\

= \frac{4 \times 2 + 8.4 \times (-6.1) }{4 + 8.4} \\

= \frac{- 43.24}{12.4}\\

= - 3.487 m/s

7 0
3 years ago
A spring has a constant k= 10.32 N/m and is hung vertically. A 0.400kg mass is suspended from the spring. What is the displaceme
alukav5142 [94]

Answer:

displacement (x) = 0.003798 meters

Explanation:

from the fact that the string is hung vertically we can deduce that:

Total force acting on the mass = Fs (by spring) + Fg (by gravity)

<em>where</em>

Fs = k*x , x is the displacement..

Fg = m*g

then:

Ftot = m*a, <em>but a = 0 m/(s^2) because the mass becames stationary.</em>

Ftot = 0

Fs + Fg = 0

<em>by direction, take down as negative.</em>

Fs - Fg = 0

k*x = m*g

x = m*g/k = [(0.400)(9.8)]/(10.32)

  = 0.3798 meters

4 0
3 years ago
contractor will use a package emulsion having a specific gravity of 1.25 and relative bulk strength of 130 to open an excavation
tester [92]

Answer:

The burden distance is 7 ft

Solution:

As per the question:

Specific gravity of package emulsion, SG_{E} = 1.25

Specific gravity of diabase rock, SG_{R} = 2.76

Diameter of the packaged sticks, d = 3 in

Now,

To calculate the first trail shot burden distance, B:

B = [\frac{2SG_{E}}{SG_{R}} + 1.5]\times d

B = [\frac{2\times 1.25}{2.76} + 1.5]\times 3 = 7.22

B = 7 ft

5 0
3 years ago
Physics question 28 plz help me
Alexus [3.1K]

Answer:

a. I = 30 A

b. E = 1080000 J = 1080 KJ

c. ΔT = 12.86°C

d. Cost = $ 4.32  

Explanation:

a.

The current in the coil is given by Ohm's Law:

V = IR\\I = \frac{V}{R}

where,

I = current = ?

V = Voltage = 120 V

R = Resistance = 4 Ω

Therefore,

I = \frac{120\ V}{4 \Omega}\\

<u>I = 30 A</u>

<u></u>

b.

The energy can be calculated as:

E = VIt\\E = (120\ V)(30\ A)(5\ min)(\frac{60\ s}{1\ min})\\

<u>E = 1080000 J = 1080 KJ</u>

<u></u>

c.

For the increase in the temperature of water:

E = mC\Delta T\\

where,

m = mass of water = 20 kg

C = specific heat of water = 4.2 KJ/kg.°C

Therefore,

1080\ KJ = (20\ kg)(4.2\ KJ/kg.^oC)\Delta T

<u>ΔT = 12.86°C</u>

<u></u>

d.

First, we will calculate the total energy consumed:

E=(Power)(Time)\\E=VI(Time)\\E = (120\ V)(30\ A)(0.5\ h/d)(30\ d)\\E = 54000\ Wh\\E = 54 KWh

Now, for the cost:

Cost = (Unit\ Cost)(Energy)\\Cost = (\$ 0.08\KWh)(54\ KWh)

<u>Cost = $ 4.32</u>

7 0
3 years ago
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