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Komok [63]
3 years ago
12

Consider a series LRC-circuit in which C-120.0 uF. When driven at a frequency w = 200.0 rad s-1 the com ples impedance is given

by Z-(100.0-J10.0) Ω. (a) Calculate (i) the reactances X1 and Xc of the circuit at w = 200.0 rad s-1, ii) the inductance of the circuit. (b) Calculate the resonant angular frequency of the circuit. Hence, calculate the driving frequencies for which the average power in the circuit is half the reso- nant power [Hint: the solutions to the quadratic formula: az? + bx + c 0 are given by: -4ac) /2a.
Physics
1 answer:
Lina20 [59]3 years ago
4 0

Answer:

(a). (i). The reactants are X_{L} =31.66\ \Omega .

(II). The inductance of the circuit is 0.1583 Henry.

(b). The resonant angular frequency is 229.4 rad/s.

Explanation:

Given that,

Capacitor = 120.0 μC

Frequency = 200.0 rad/s

Impedance = 100.0 -10j

(I). We need to calculate the X_{C}

X_{C}=\dfrac{1}{C\times\omega}

Put the value into the formula

X_{C}=\dfrac{1}{120\times10^{-6}\times200}

X_{C}=41.66\ \Omega

(II). We know that,

Formula of impedance is

Z=\sqrt{R^2+X_{L}^2+X_{C}^2}...(I)

Given equation of impedance is

Z=(100-10j)...(II)

On Comparing of equation (I) and (II)

R = 100

X_{L}-X_{C}=-10

Now, put the value of  X_{C}

X_{L=41.66-10

X_{L}=31.66\ \Omega

We need to calculate the inductance

Using formula of inductance

X_{L}=\omega\times L

Put the value into the formula

L=\dfrac{X_{L}}{\omega}

L=\dfrac{31.66}{200}

L=0.1583\ Henry

(b). We need to calculate the resonant angular frequency

Using formula of the resonant angular frequency

angular\ frequency =\dfrac{1}{\sqrt{L\times C}}

angular\ frequency =\dfrac{1}{\sqrt{0.1583\times120\times10^{-6}}}

angular\ frequency =229.4\ rad/s

Hence, (a). (i). The reactants are X_{L} =31.66\ \Omega .

(II). The inductance of the circuit is 0.1583 Henry.

(b). The resonant angular frequency is 229.4 rad/s.

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