When two negatively charged objects are brought near each other, a repulsive force is produced. When two positively charged objects are brought near each other, a similar repulsive force is produced. When a negatively charged object is brought near a positively charged object, an attractive force is produced.
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Answer and explanation:
Let be the velocity of a body projected vertically up, 1 second before it reaches its maximum height. We know, from the kinematics equations, that the distance traveled in an interval of time is equal to:
Then, in the last second, the distance traveled is equal to:
But the velocity is related to the time by the equation:
And substituting this expression in the equation above, we obtain:
It means that the distance traveled by the body in the last second of its motion is a constant, independent of its initial velocity.
Vi =0 ( as car starts from rest )
Acceleration= a = 5m/s²
t =12sec
Vf =Vi + at
Vf= 0 + (5m/s²) (12s)
Vf=60 m/s
Ohm’s Law:
V = IR
V = battery voltage, I = current, R = resistance
Top-left circuit:
V = 25V, I = 5A, R = 5ohm
25 = 5•5
25 = 25
This circuit is correct.
Top-right circuit:
V = 18V, I = 6A, R = 4ohm
18 = 6•4
18 =/= 24
This circuit is incorrect.
Bottom-left circuit:
V = 56V, I = 7A, R = 8ohm
56 = 7•8
56 = 56
This circuit is correct.
Bottom-right circuit:
V = 20V, I = 5A, R = 4ohm
20 = 5•4
20 = 20
This circuit is correct.
The following circuits are correct: top-left, bottom-left, and bottom-right.
Heat and light are released!