Answer:
10 km/L
Explanation:
Given the following from question:
Efficiency of car engine = 25% = 0.25
Average force = 1000 N
Gasoline energy content = 40,000,000 J/L
therefore:
Energy utilized effectively = Efficiency of car engine * Gasoline energy content
Energy utilized effectively = 0.25 * 40,000,000 = 10,000,000 J/L
Distance obtain by car in kilometer per meter = Energy utilized effectively/Average force
Distance obtain by car in kilometer per meter = 10,000,000/1000 = 10,000 m/L = 10 km/L
10,000 meter per liter = 10 kilo meter per liter
