All categories

3 years ago

How many

Physics

1 answer:

ludmilkaskok [199]3 years ago

5 0

Answer:

10 km/L

Explanation:

Given the following from question:

Efficiency of car engine = 25% = 0.25

Average force = 1000 N

Gasoline energy content = 40,000,000 J/L

therefore:

Energy utilized effectively = Efficiency of car engine * Gasoline energy content

Energy utilized effectively = 0.25 * 40,000,000 = 10,000,000 J/L

Distance obtain by car in kilometer per meter = Energy utilized effectively/Average force

Distance obtain by car in kilometer per meter = 10,000,000/1000 = 10,000 m/L = 10 km/L

10,000 meter per liter = 10 kilo meter per liter

You might be interested in

The potential energy for a certain mass moving in one dimension is given by U(x)=(2.0J/m3)x3−(15J/m2)x2+(36J/m)x−23JU(x)=(2.0J/m

Angelina_Jolie [31]

Answer:x=2 and x=3

Explanation:

Given

Potential Energy for a certain mass is

$U(x)=2x^3-15x^2+36x-23$

and we know force is given by

$F=-\frac{\mathrm{d} U}{\mathrm{d} x}$

$F=-(2\times 3x^2-15\times 2x+36)$

For Force to be zero F=0

$\Rightarrow 6x^2-30x+36=0$

$\Rightarrow x^2-5x+6=0$

$\Rightarrow x^2-2x-3x+6=0$

$\Rightarrow (x-2)(x-3)=0$

Therefore at x=2 and x=3 Force on particle is zero.

8 0

3 years ago

Two cars start a race with initial velocity 7ms-1 and 4ms-1 respectively.Their acceleration are 0.4ms-2 and 0.5ms-2 respectively

Ronch [10]

The distance of the track is 600 m

Explanation:

The two cars move by uniformly accelerated motion, so we the distance they cover after a time t is described by the following suvat equation

$d=ut+\frac{1}{2}at^2$

where

u is the initial velocity

a is the acceleration

For car 1, we have

$d_1 = u_1 t + \frac{1}{2}a_1 t^2$

where

$u_1 = 7 m/s$ is the initial velocity of car 1

$a_1 = 0.4 m/s^2$ is the acceleration of car 1

So the equation can be rewritten as

$d_1 = 7t + 0.2t^2$

For car 2, we have

$d_2 = u_2 t + \frac{1}{2}a_2 t^2$

where

$u_2 = 4 m/s$ is the initial velocity of car 2

$a_2 = 0.5 m/s^2$ is the acceleration of car 2

So the equation can be rewritten as

$d_2= 5t + 0.25t^2$

The two cars finish the race at the same time: this means that they cover the same distance in the same time t, so we can write

$d_1 = d_2\\7t + 0.2t^2=5t + 0.25t^2$

And solving for t, we find

$2t - 0.05t^2= 0\\t(2-0.05t)=0$

Which gives two solutions:

t = 0 (initial instant)

t = 40 s

Therefore, the distance of the track is

$d_1 = 7t +0.2t^2 = 7\cdot 40+0.2\cdot 40^2=600 m$

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

7 0

4 years ago

On a transverse wave, the crest isa. the highest part of the wave.

Greeley [361]

I think it is C) the resting position of the wave.

3 0

3 years ago

Why does a hot air balloon float?

GaryK [48]

The most accurate answer among the choices would be the fourth one, because if the weight of the air displaced is greater than the balloon's weight, the balloon will float upwards. Density of the air also plays a part. Hot air = less dense. Hope my answer has come to your help.

8 0

3 years ago

Read 2 more answers

What is the weight of a 20kg stone?

worty [1.4K]

Answer: w = 200N

Explanation:

w = mg

m = 20kg

g = 10m/s^ (approximately)

w = 20kg . 10m/s^

w = 200N