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Oksana_A [137]
3 years ago
8

Write a class declaration named Circle with a private member variable named radius. Write set and get functions to access the ra

dius variable, and a function named getArea that returns the area of the circle.the area calcilated as?
Engineering
1 answer:
Leona [35]3 years ago
8 0

Answer:

Explanation:

The following code is in C# Language

   public class Circle

   {

       private float radius;

       public float Radius

       {

           get { return radius; }

           set { radius = value; }

       }

       public void GetArea()

       {

           Console.WriteLine("The area of the circle is ", Math.PI* Radius  *Radius);

       }

 

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Determine the hydraulic radius for the following rectangular open channel width =23m water depth =3m
Romashka-Z-Leto [24]

Answer:

2.379m

Explanation:

The width = 23m

The depth = 3m

The radius is denoted as R

The wetted area is = A

The perimeter perimeter = P

Hydraulic radius

R = A/P

The area of a rectangular channel

= Width multiplied by Depth

A = 23x3

A = 69m²

Perimeter = (2x3)+23

P = 6+23

P= 29

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= 2.379m

This answers the question

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3 years ago
1. A piston having a diameter of 5.48 inches and a length of 9.50 in slides downward with a velocity, V, through a vertical pipe
const2013 [10]

Answer:

V = 0.00459 ft/s  

Explanation:

Since the Piston is moving downwards with a constant velocity V, from the first Newton’s law we know that all vertical forces, must have zero resultant (their sum over vertical axis must equal to zero). Therefore, force that pulls the piston down, is equalized by force of viscous friction Fd= Fvf = 0.5lb (lb here is the pound-force unit). We will relate F ѵ f  with τ and from that derive the equation for V.

Fѵf = τ  . A

Where τ  = µ. du/dy = µ . V/b  , and A = π . D . l from this Follows:

Fѵf= (V.  A .µ )/b     V= ( Fѵf .b )/(A.µ)    

Placing all the known values in the equation ( remember  to transform inches to feet, by multiplying inches values with the factor 1/12), we obtain :  

ft2

V = ((0.5lb)   .   (0.002/12 ft))/(π   .   (5.48/12 ft)  .  (9.50/12 ft)  .  (0.016 lb.s/(ft^2 )))

V = 0.00459 ft/s  

Download docx
3 0
3 years ago
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