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ella [17]
2 years ago
5

A 25.0-milliliter sample of HNO3(aq) is neutralized by 32.1 milliliters of 0.150 M KOH(aq). What is the molarity of the HNO3(aq)

?
(1) 0.117 M (3) 0.193 M
(2) 0.150 M (4) 0.300 M
Chemistry
2 answers:
dusya [7]2 years ago
4 0
The answer is (3) 0.193M. To find the molarity of HNO3, you just need to use the M1V1=M2V2 equation (no need to worry about ionization constants because HNO3 is monoprotic and KOH dissociates 1:1). Since the molarity you are looking for is M1, you get M1=M2V2/V1=(0.150)(32.1)/25.0= 0.193M
lubasha [3.4K]2 years ago
3 0

<u>Answer:</u> The correct answer is Option 3.

<u>Explanation:</u>

To calculate the molarity of the acid, we use the equation:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of acid

M_2\text{ and }V_2 are the molarity and volume of base

We are given:

M_1=?M\\V_1=25mL\\M_2=0.150M\\V_2=32.1mL

Putting values in above equation, we get:

M_1\times 25=0.15\times 32.1\\\\M_1=0.193M

Hence, the correct answer is Option 3.

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2 years ago
A sample of glucose contains 1.250x10^21 carbon atoms, how many atoms of hydrogen does it contain?
dybincka [34]

Answer:

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One of the ways you could do  this is to notice that for every carbon atom there are two Hydrogen atoms. You can state this more formally by using the formula to set up a ratio: 12/6 = hydrogen to Carbon

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You could do this more formally by setting up a proportion.

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6*x = 12 * 1.25*10^21                                           Combine the right

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2 years ago
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Zeff = Z - S

Silicon has 14 protons; its electron configuration is [Ne] 3s2 3p2. Its non-valence electrons is in the n = 1 and n =2 shells. There are 2 electrons in n = 1 and 8 in n = 2, so there are a total of 10 non-valence electron.

<span><span>Z<span>eff</span></span>= 14−10= 4</span>

So, the answer is 4.
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