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3 years ago

What are the risks of biohacking? Do you think the risks of biohacking outweigh the advantages? Why or why not?

Engineering

1 answer:

maksim [4K]3 years ago

5 0

Explanation:

Despite its futuristic outlook and results biohacking remains a largely unsupervised, dangerous if not illegal movement. Though the research and results produced by biohackers is ground breaking, it also breaks several ethical codes on human experimentation and endangering live of several humans.

I agree with the fact that risks outweigh advantages, but you can do things like:

- 3D Printing Body Parts

- Finding Cures

- Correcting Deformites.

The only issue is that it's illegal, unfortunately.

You might be interested in

How do engineering and technology impact the natural world and environment

ddd [48]

Answer:

Answer to the following question is as follow.

Explanation:

Civil engineering industrial development projects have a significant influence on the environment, particularly in terms of excessive noise, environmental pollution, and land shrinkage.

Engineers have totally transformed our environment, from contemporary dwellings to bridges, space flight, automobiles, and cutting-edge mobile technologies. Engineers utilise their expertise to build new and exciting prospects and address any difficulties that may occur, and they employ their innovative ideas to accomplish so.

8 0

3 years ago

Discuss four (4) advantages of direct and indirect water supply system.

Reil [10]

Answer and Explanation:

Some of the advantages of direct water supply system are:

Smaller size of the cistern
No risk of polluted water
Ease of installation
Lower pipe work

Some of the advantages of indirect water supply system are:

It can be pumped completely
Lower demand on the main source
Minimization of wear and tear on taps
Larger size of the cistern.

7 0

3 years ago

Read 2 more answers

A hanging wire made of an alloy of nickel with diameter 0.19 cm is initially 2.8 m long. When a 59 kg mass is hung from it, the

Makovka662 [10]

Answer:

Young's modulus for this alloy of nickel is 1.997×10^11 N/m^2

Explanation:

Young's modulus = stress/strain

Stress = Force (F)/Area (A)

F = mg = 59 kg × 9.8 m/s^2 = 578.2 N

A = πd^2/4 = 3.142 × (0.19/100)^2/4 = 2.836×10^-6 m^2

Stress = 578.2/2.836×10^-6 = 2.039×10^8 N/m^2

Strain = extension/length = 2.86×10^-3 m/2.8 m = 1.021×10^-3

Young's modulus = 2.039×10^8/1.021×10^-3 = 1.997×10^11 N/m^2

4 0

3 years ago

An aluminum bar 125 mm long with a square cross section 16 mm on an edge is pulled in tension with a load of 66,700 N and experi

AfilCa [17]

Answer: the modulus of elasticity of the aluminum is 75740.37 MPa

Explanation:

Given that;

Length of Aluminum bar L = 125 mm

square cross section s = 16 mm

so area of cross section of the aluminum bar is;

A = s² = 16² = 256 mm²

Tensile load acting the bar p = 66,700 N

elongation produced Δ = 0.43

Δ = PL / AE

we substitute

0.43 = (66,700 × 125) / (256 × E)

0.43(256 × E) = (66,700 × 125)

110.08E = 8337500

E = 8337500 / 110.08

E = 75740.37 MPa

Therefore, the modulus of elasticity of the aluminum is 75740.37 MPa

4 0

2 years ago

A 10-mm steel drill rod was heat-treated and ground. The measured hardness was found to be 290 Brinell. Estimate the endurance s

grandymaker [24]

Answer:

the endurance strength $S_e$ = 421.24 MPa

Explanation:

From the given information; The objective is to estimate the endurance strength, Se, in MPa .

To do that; let's for see the expression that shows the relationship between the ultimate tensile strength and Brinell hardness number .

It is expressed as:

$200 \leq H_B \leq 450$

$S_{ut} = 3.41 H_B$

where;

$H_B$ = Brinell hardness number

$S_{ut}$ = Ultimate tensile strength

From ;

$S_{ut} = 3.41 H_B$ ; replace 290 for $H_B$ ; we have

$S_{ut} = 3.41 (290)$

$S_{ut} =$ 988.9 MPa

We can see that the derived value for the ultimate tensile strength when the Brinell harness number = 290 is less than 1400 MPa ( i.e it is 988.9 MPa)

So; we can say

$S_{ut} < 1400$