Ask question

Ask question

All categories

4 years ago

11

In this experiment, the_____was intentionally manipulated. This was the independent variable. The dependent variable measured wa

s the____ . 1. fan speed 2. mass 3.acceleration

2 answers:

stellarik [79]4 years ago

6 0

Answer:

1.) Fan Speed was manipulated

2.) The acceleration was measured

Explanation:

julia-pushkina [17]4 years ago

6 0

Fan speed and acceleration

You might be interested in

7Unreasonable results A dolphin in an aquatic show jumps straight up out of the water at a velocity of 15.0 m/s.

polet [3.4K]

Answer: See below

Explanation:

a. What is know:

Dolphin's Initial Velocity (Vo) = 15.0 m/s

Gravity Acceleration = 9.8 $m/s^{2}$

We also know that the time the dolphin is in the air it equals to twice the time it takes to reach the highest point on the jump (t).

Total Time (Tt) = 2 * t

b. To choose appropiated equation, we notice that it is know the Dolphin's Initial Velocity and the gravity. It not know the distance it travels or the time it takes, however, because goes up, it can be know the velocity on the highest point (Vf), which is zero. After reaching this point the Dolphin will fall back again. So it is know:

Vf = 0

Because know we know the final velocity we can calculate the distance traveled to get to that velocity under the gravity des-aceleration, we the following equation:

$Vf^{2} = Vo^{2} + 2 * a *d$

Where the accelaration will be gravity, with a negative sign because it has a diference direction that the velocity, and Vf being 0, simplify the equation. Knowing all the values, we search the distance (d).

$d = \frac{Vo^{2} }{2g}$

Changing the values:

d = 11.46 m

c. To know the time is very easy. Because we know the initial velocity, the gravity and the final velocity. We can use the following equation

$Vf = Vo - gt$

Searching for time we get:

$t = \frac{Vo}{g}$

Which give us a time of: 1.53 s

This is the time it takes to get to the highest point. By doubling it, we know how much it took the dolphin to jump to the highest point and fall back to the water, which is the time it was on air.

Tt = 2 * 1.53 s

Tt= 3.06 s

8 0

3 years ago

Please help ill give brainliest.

oee [108]

The answer is the last option "Respiration"

3 0

3 years ago

Read 2 more answers

Which formula is used to calculate the mass of an object if the force and acceleration are known? m = Fa m = m = m = F – a

SOVA2 [1]

I'm pretty sure it is m = Fa

7 0

3 years ago

Read 2 more answers

Aman tosses a jart upward with a velocity of 14.1 m/s a 60° angle

crimeas [40]

Answer:

hold on let me check my answer

Explanation:

8 0

4 years ago

A cannonball fired with an initial speed of 40 m/s and a launch angle of 30 degrees from a cliff that is 25m tall.

KATRIN_1 [288]

We know that the ball traveled with an initial velocity of 40m/s at a 30° angle above the horizontal. The image below shows how much of this velocity was upward velocity and how much was horizontal velocity. Upward velocity was 20 m/s and horizontal velocity was √(40) m/s, or 2√(10) m/s. We get these numbers from the ratios of the 30-60-90 triangle.

a) What is the flight time of the cannonball?
The flight time of the cannonball can be found by finding the time at which the upward velocity equals zero (the top of the ball's trajectory) and then finding how long it took to hit the ground after that point.

To find where upward velocity equals zero:
V = Vi - a(t) , where V equals vertical velocity, Vi equals initial vertical velocity, and a equals acceleration due to gravity (-9.8 m/s²)
V = 20 - 9.8(t) Set V equal to zero, because we want to find the moment when the ball reached the peak of its travel path
0 = 20 -9.8t Add 20 to both sides, then divide by 9.8
t = 2.041
This is the point where the ball was at the top of its trajectory.

At this point, How high was the ball?
d = Vi x t + (1/2) (a) (t²) , where d is distance traveled
d = 20(2.041) + (1/2) (-9.8) (2.041²)
d = 20.388
Remember that the ball was launched from 25 m above the ground, so add 25 to the height that the ball traveled from this point:
25 + 20.388 = 45.388
This was the height the ball reached before it started to come down. Plug this into the distance formula to see how long it took to hit the ground. Remember that this is similar to the ball being dropped from rest from this height, since vertical velocity was zero.
45.388 = (0)(t) - (1/2) (-9.8) (t²) Multiply both sides by (-2/-9.8)
9.26 = t²
t = 3.043
We know that it took 2.041 seconds to reach the peak height, and 3.043 seconds to come down.
Total flight time = 2.041 + 3.043 = 5.084 seconds

Remember that, neglecting air resistance, the ball will maintain the same horizontal velocity the entire time. This means the horizontal velocity was 10√2 during the entire flight time.
distance = velocity * time = 5.084 * 10√2 = 32.154

5 0

4 years ago