Answer:
V₀ = 5.47 m/s
Explanation:
The jumping motion of the Salmon can be modelled as the projectile motion. So, we use the formula for the range of projectile motion here:
R = V₀² Sin 2θ/g
where,
R = Range of Projectile = 3.04 m
θ = Launch Angle = 41.7°
V₀ = Minimum Launch Speed = ?
g = 9.81 m/s²
Therefore,
3.04 m = V₀² [Sin2(41.7°)]/(9.81 m/s²)
V₀² = 3.04 m/(0.10126 s²/m)
V₀ = √30.02 m²/s²
<u>V₀ = 5.47 m/s</u>
Answer:
C. The forces are balanced.
Explanation:
Every answer other than C means the object moved.
Answer:
A dictatorship or tyranny.
Explanation:
Answer:
Approximately , assuming that the acceleration of this ball is constant during the descent.
Explanation:
Assume that the acceleration of this ball, , is constant during the entire descent.
Let denote the displacement of this ball and let denote the duration of the descent. The SUVAT equation would apply.
Rearrange this equation to find an expression for the acceleration, , of this ball:
.
Note that and in this question. Thus:
.
Let denote the mass of this ball. By Newton's Second Law of Motion, if the acceleration of this ball is , the net external force on this ball would be .
Since and , the net external force on this ball would be:
.
Answer:
a) v = 4.4 m/s
b) F = 400 N
Explanation:
a) ½kx² = ½mv²
v = √(kx²/m)
F = kx
v = √(Fx/m)
v = √(800(0.012) / 0.5) = √19.2 = 4.3817...
b) Fd = ½mv²
F = mv²/2d
F = 0.5(19.2) / (2(0.012) = 400 N