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frez [133]
3 years ago
9

Suppose a greenhouse is to be constructed to keep plants warm in the winter. Which material should be used for the windows of th

e greenhouse? Material (A, B, C, or D) Should be used because it will A. let the most solar radiation into the greenhouse. B. absorb radiation emitted by the Sun while letting through most radiation from the interior of the greenhouse. C. absorb the most solar radiation. D. absorb radiation from the interior of the greenhouse while letting through most radiation from the Sun.
Physics
1 answer:
Anastasy [175]3 years ago
4 0

Answer:

the answers, material D meets the requested characteristics

Explanation:

The objective of an insulating material for the house, must allow solar radiation to enter, so that the plants can perform photosynthesis and must prevent radiation from inside the house from being lost.

Therefore the material must meet two conditions be transparent to sunlight and be absorbed from the radiation coming from the house; this is to leave for visible light and absorb infrared radiation

Reviewing the answers, material D meets the requested characteristics

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On a 100km track , a train travels the first 30km with a speed of 30km/h . How fast the train travel the next 70 km if the avera
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Solution :-

Given :

Distance 1 = 30 km

Distance 2 = 70 km

We know that speed = distance/time

and, Average speed = total distance/total time taken

When the train acquired a speed of 30 km/hr, the time taken = 30/30 = 1 hour

Average speed = 9distance 1 + distance 2)/(time 1 + time 2)

AS time 2 or t2 is time taken for the second part of the journey of 70 km

⇒ 40 = 100/(1 + t2)

⇒ 40 + 40t2 = 100

⇒ 40t2 = 100 - 40

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⇒ t2 = 60/40

⇒ t2 = 1.5

So, t2 or time taken to travel the second part of the journey is 1.5 hours.

Speed of the second part of the journey = distance 2/time 2

⇒ 70/1.5

⇒ 46.666 km/hr or 46.7 km/hr.

Hence the answer is = 46.666 km/hr or 46.7 km/hr.

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3 0
3 years ago
A ball is thrown vertically upward from the top of a building 112 feet tall with an initial velocity of 96 feet per second. The
nordsb [41]

Answer:

t=6.96s

Explanation:

From this exercise, our knowable variables are <u>hight and initial velocity </u>

v_{oy}=96ft/s

y_{o}=112ft

To find how much time does the <u>ball strike the ground</u>, we need to know that the final position of the ball is y=0ft

y=y_{o}+v_{oy}t+\frac{1}{2}gt^{2}

0=112ft+(96ft/s)t-\frac{1}{2}(32.2ft/s^{2})t^{2}

Solving for t using quadratic formula

t=\frac{-b±\sqrt{b^{2}-4ac } }{2a}

a=-\frac{1}{2} (32.2)\\b=96\\c=112

t=-0.999s or t=6.96s

<u><em>Since time can't be negative the answer is t=6.96s</em></u>

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