Answer:
The final velocity of the thrower is 
and the final velocity of the catcher is 
.
Explanation:
Given:
The mass of the thrower, 
.
The mass of the catcher, 
.
The mass of the ball, 
.
Initial velocity of the thrower, 
Final velocity of the ball, 
Initial velocity of the catcher, 
Consider that the final velocity of the thrower is 
. From the conservation of momentum,
Consider that the final velocity of the catcher is 
. From the conservation of momentum,
Thus, the final velocity of thrower is 
and that for the catcher is 
.
Answer:
Statement 2 is wrong
Explanation:
To check the statements in this exercise, let's describe the main properties of electromagnetic waves. Let's describe the characteristics
* they are transverse waves
* formed by the oscillations of the electric and magnetic fields
* the speed of the wave is the speed of light
with these concepts let's review the final statements
1) True. Formed by the oscillation of the two fields
2) False. They are transverse waves
3) True. Can travel by vacuum as they are supported by oscillations of the electric and magnetic fields
4) True. They all have the same speed of light
Statement 2 is wrong
Answer:
hey mate here is your answer
So if an object has a very small velocity (not moving very far over time, even though a large force may be applied to it, the Power will remain small. ... Stepping on the gas, or "speeding up" the car, is applying a force which will increase velocity and increase power.
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The first person = A
The second one = B
velocity of A = 3 km / h
velocity of B = 4 km / h
Distance of A = 3t
Distance of B = 35 - 4t
At what time do they meet?
3t = 35 - 4t
7t = 35
t = 5 hours
7 a.m. + 5 hours = 12 p.m.
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Weight = electric force
<span>mg = qE </span>
<span>6.64x10^-27 x 9.81 = (2 x 1.60x10^-19) E
</span>qE =mg,
<span>E = mg/q = 6.64•10^-27•9.8/2•1.6•10^-19 =2.03•10^-7 V/m</span>
