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Bas_tet [7]
3 years ago
5

The sound from a single source can reach point O by two different paths. One path is 20.0 m long and the second path is 21.0 m l

ong. The sound destructively interferes at point O. What is the minimum frequency of the source if the speed of sound is 340 m/s?
Physics
1 answer:
aleksandrvk [35]3 years ago
7 0

Answer:

minimum frequency = 170 Hz

Explanation:

given data

One path long = 20 m

second path long = 21 m

speed of sound = 340 m/s

solution

we get here destructive phase that is path difference of minimum \frac{\lambda}{2}

here  λ is the wavelength of the wave

so path difference will be

21 - 20 = \frac{\lambda}{2}  

λ = 2 m

and

velocity that is express as

velocity = frequency × wavelength    .............1

frequency  = \frac{340}{2}  

minimum frequency = 170 Hz

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Beth, a construction worker, attempts to pull a stake out of the ground by pulling on a rope that is attached to the stake. The
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Answer:

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Explanation:

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For a right triangle :

sinβ = y/h formula (1)

cosβ = x/h formula (2)

x: side adjacent to the β angle

y:  opposite side of the β angle

h: hypotenuse

Known data

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8 0
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spin [16.1K]
Average velocity =

      (displacement) / (time for the displacement)
and
      (direction of the displacement) .

Displacement =

      (distance from the start-point to the end-point)
and
      (direction from the start-point to the end-point)   .

When Ben is 200 meters from the corner store,
he is (500 - 200) = 300 meters from his house.

His displacement is

         300 meters in the direction
                             from his house to the neighbor .


His average velocity is

         (300/910) =  0.33 meters per second, in the
                               direction from his house to the neighbor .


7 0
3 years ago
Read 2 more answers
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