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Bas_tet [7]
4 years ago
5

The sound from a single source can reach point O by two different paths. One path is 20.0 m long and the second path is 21.0 m l

ong. The sound destructively interferes at point O. What is the minimum frequency of the source if the speed of sound is 340 m/s?
Physics
1 answer:
aleksandrvk [35]4 years ago
7 0

Answer:

minimum frequency = 170 Hz

Explanation:

given data

One path long = 20 m

second path long = 21 m

speed of sound = 340 m/s

solution

we get here destructive phase that is path difference of minimum \frac{\lambda}{2}

here  λ is the wavelength of the wave

so path difference will be

21 - 20 = \frac{\lambda}{2}  

λ = 2 m

and

velocity that is express as

velocity = frequency × wavelength    .............1

frequency  = \frac{340}{2}  

minimum frequency = 170 Hz

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Combining this equation with the first equation we have:

(\frac{T_{1}p_{2}}{T_{2}p_{1}})^{\gamma -1} = \frac{T_{2}}{T_{1}}

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Let's assume the initial temperature and pressure as 25 °C = 298 K and 1 atm = 1.01 * 10⁵ Pa, in a normal conditions.

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