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Nadusha1986 [10]
3 years ago
11

Two unknown molecular compounds were being studied. A solution containing 5.00 g of compound A in 100. g of water froze at a low

er temperature than a solution containing 5.00 g of compound B in 100. g of water. Which compound has the greater molar mass? Explain how you arrived at your answer.
Chemistry
1 answer:
Shtirlitz [24]3 years ago
7 0

Answer:

Compound B.

Explanation:

The freezing point depression is a colligative property. It depends on the number of particles (moles) present in the solution.

\Delta T_{\text{f}} = K_{\text{f}} b

where b is the molal concentration

b = \dfrac{\text{moles of solute}}{\text{kilograms of solvent}}\\\\n = \dfrac{\text{mass}}{\text{molar mass}} = \dfrac{m}{M}

If m is constant (5 g), then

n \propto \dfrac{1}{M}

The compound with the greater molar mass has fewer moles and therefore fewer particles to depress the freezing point.

That must be Compound B, because Compound A has the lower freezing point.

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Hello
nordsb [41]

Answer:

The ratio of the number of atoms of gold and silver in the ornament is 197 : 1080.

Explanation:

Let the mass of silver ornament be x.

Mass of gold polished on an ornament = 1% of x= 0.1 x

Moles of silver =\frac{x}{108 g/mol}

Number of atoms = Moles\times N_A

Where : N_A = Avogadro number

Moles of gold =\frac{0.1x}{197 g/mol}

Silver atoms =\frac{x}{108 g/mol}\times N_A

Gold atoms =\frac{0.1x}{197 g/mol}\times N_A

The ratio of the number of atoms of gold and silver in the ornament:

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3 0
3 years ago
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