Answer: d. I or II
Explanation: A traveling wave has speed that depends on characteristics of a medium. Characteristics like linear density (μ), which is defined as mass per length.
Tension or Force () is also related to the speed of a moving wave.
The relationship between tension and linear density and speed is ginve by the formula:
So, for the traveling waves generated on a string fixed at both ends described above, ways to increase wave speed would be:
1) Increase Tension and maintaining mass and length constant;
2) Longer string will decrease linear density, which will increase wave speed, due to their inversely proportional relationship;
Then, ways to increase the wave speed is
I. Using the same string but increasing tension
II. Using a longer string with the same μ and T.
F12=(8.98×10↑9 m/f)(1C)(-4C)/(4m)↑2=(8.98×10↑9 N·m↑2/c↑2)(-0.25C↑2/m↑2)~2.25×10↑9N i hope thats right
Answer:
48 m
Explanation:
An object is said to be moving in uniform motion if its velocity is constant.
For an object in uniform motion, its average speed is given by the equation:
where
v is the average speed
d is the distance covered
t is the time taken
For the object in this problem, we have:
v = 6.0 m/s is the average speed
t = 8.0 s is the time taken
Solving for d, we find the distance traveled:
Given:
ΔT = 38 - 26 = 12°C, temperature change
Q = 11.3 J, heat input
c = 0.128 J/(g-°C), specific heat of lead
Let m = the mass of the lead.
Then
Q = m*c*ΔT
(m g)*(0.128 J/(g-°C))*(12 °C) = 11.3 J
1.536m = 11.3
m = 7.357 g
Answer: 7.36 g (2 sig. figs)