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4 years ago

What is most often given a value of 0 to describe an object's position on a straight line?

1 answer:

5 0

Answer: reference.

To describe the position on a straigh line (one dimension motion) it is very common to use reference 0, i.e. you describe the position from the origin.

For example, to describe the position of the house from the corner, you use the corner as the point 0, which is the reference, and so the position ot the house will be the distance from the corner (rerence 0).

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The aorta is the main artery from the heart. a typical aorta has an inside diameter of 1.8 cm and carries blood at speeds of up

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Answer:

Explanation:

Volume per unit time flowing will be conserved

a₁v₁ = a₂ v₂

π r₁² x v₁ = π r₂² x v₂

(0.9 x 10⁻²)² x .35 = ( .45 x 10⁻² )² x v₂

v₂ = 1.4 m / s

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3 years ago

. Prior to Remy's trip to Cleveland, his uncle tells him about this amazing barbecue restaurant there and raves about

Andrews [41]

whats the restraunt called

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3 years ago

What is the momentum of a volleyball with a velocity of 50 mph and a mass of .5 kg?

Romashka-Z-Leto [24]

The formula for momentum is p=mv (mass multiplied by velocity), so in this problem, p=50(.5)=25=p or in other words, momentum.

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4 years ago

Use the drop down menu to complete the sentence. Resistance is measured in units called...

liubo4ka [24]

Ohms is the correct answer

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4 years ago

Read 2 more answers

4. Johnny exerts a 3.55 N rightward force on a 0.200-kg box to accelerate it across a low-friction track. If the total resistanc

muminat

a) $15.2 m/s^2$

b) 1.96 N

c) 1.96 N

Explanation:

To find the acceleration of the box, we apply Newton's second law of motion:

$\sum F=ma$

where

$\sum F$ is the net force on the box

m is the mass of the box

a is its acceleration

Here we have to consider the horizontal direction, which is the one in which the box is moving. The net force is given by:

$\sum F=3.55 N - 0.52 N=3.03 N$

which is the difference between the forward force and the resistive force. Then we have

m = 0.200 kg (mass of the box)

Therefore, the acceleration of the box is:

$a=\frac{\sum F}{m}=\frac{3.03}{0.200}=15.2 m/s^2$

The gravitational force (also called weight) is the force with which an object is pulled by the Earth towards the Earth's centre.

It is given by

$F_g = mg$

where

m is the mass of the object

g is the acceleration due to gravity

In this problem, we have:

m = 0.200 kg is the mass of the box

$g=9.8 m/s^2$ is the acceleration due to gravity

Therefore, the gravitational force on the box is:

$F_g=(0.200)(9.8)=1.96 N$

The normal force is the force with which a surface pushes back on an object.

For an object lying on a flat surface, there are two forces acting along the vertical direction:

- The gravitational force, $F_g$ , which pushes the object downward

- The normal force, N, which pushes the object upward

As the object is at rest, the vertical acceleration of the object is zero, therefore according to Newton's second law of motion, the net force must be zero:

$\sum F=F_g-N=0$

Which means that the normal force is equal to the gravitational force:

$N=F_g$

And so, for the box in this problem, the normal force is

$N=1.96 N$

6 0

4 years ago