Answer:
![p[H+] = 10.042](https://tex.z-dn.net/?f=p%5BH%2B%5D%20%3D%2010.042)
Explanation:
As we know that
......eq (1)
we will calculate the pH of OH- and then we will calculate the pH of H+
So p[OH-] ![= - log [1.10 * 10^{-4}]](https://tex.z-dn.net/?f=%3D%20-%20log%20%5B1.10%20%2A%2010%5E%7B-4%7D%5D)
Solving the right side of the equation, we get
p[OH-]
![= - [-3.958]\\= 3.958](https://tex.z-dn.net/?f=%3D%20-%20%5B-3.958%5D%5C%5C%3D%203.958)
Now we know that

Substituting the value of pOH in the above equation, we get -
![14.0 = p[H+] + 3.958\\p[H+] = 14 - 3.958\\p[H+] = 10.042](https://tex.z-dn.net/?f=14.0%20%3D%20p%5BH%2B%5D%20%2B%203.958%5C%5Cp%5BH%2B%5D%20%3D%2014%20-%203.958%5C%5Cp%5BH%2B%5D%20%3D%2010.042)
Answer:
Option C. Energy Profile D
Explanation:
Data obtained from the question include:
Enthalpy change ΔH = 89.4 KJ/mol.
Enthalpy change (ΔH) is simply defined as the difference between the heat of product (Hp) and the heat of reactant (Hr). Mathematically, it is expressed as:
Enthalpy change (ΔH) = Heat of product (Hp) – Heat of reactant (Hr)
ΔH = Hp – Hr
Note: If the enthalpy change (ΔH) is positive, it means that the product has a higher heat content than the reactant.
If the enthalpy change (ΔH) is negative, it means that the reactant has a higher heat content than the product.
Now, considering the question given, the enthalpy change (ΔH) is 89.4 KJ/mol and it is a positive number indicating that the heat content of the product is higher than the heat content of the reactant.
Therefore, Energy Profile D satisfy the enthalpy change (ΔH) for the formation of CS2 as it indicates that the heat content of product is higher than the heat content of the reactant.
False because there’s only 60% turbulence 20% heat 20% sound
The less mass an object has, the greater its gravitational force.
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