Answer:
You need 375 mL of BaCl2 solution.
Explanation:
M1V1=M2V2
Dilution formula. Substitute known values and solve for V1.
M1 = 2.0 M
M2 = 1.50 M
V2 = 500 mL
(2.0 M)(V1) = (1.50 M)(500 mL)
V1 = (1.50 M)(500 mL) / (2.0 M)
V1 = 375 mL
The volume of Sulfur dioxide-SO₂ at STP : = 102.144 L
<h3>Further explanation</h3>
Given
4.56 mol Sulfur dioxide-SO₂
Required
The volume
Solution
Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters/mol.
so for 4.56 mol :
= 4.56 x 22.4 L
= 102.144 L
Answer:
<h2><u>Reason:</u></h2>
Catalyst is used as a very fine powder and larger pieces of iron are not used. This is because the surface area of catalyst needs to be large so that more of the surface is exposed to the substrate and more of the substrate is catalyzed.
<h2><u>Important Info:</u></h2>
=> Larger Pieces of Iron has a smaller surface area than the fine particles.
=> Larger the surface area of catalysts/enzymes , more will be the reaction rate and vice versa.
Hope this helped!
<h2>~AnonymousHelper1807</h2>
That would be 58.6 oxide because if the 41.2 plus the oxide would be 48 plus the other particcles inside it so it equaled 58.6 oxide
i hope it help you a lot tell it is correct or not
