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svetlana [45]
3 years ago
10

Will velocities ever be equal?

Chemistry
1 answer:
Leni [432]3 years ago
6 0
Velocities can be equal
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Iron atoms have been detected in the sun's outer atmosphere, some with many of their electrons stripped away. what is the net el
shtirl [24]
For a proton, the charge is represented by +e
For an electron, the charge is represented by -e
The charge of an electron [e] is equal to the - 1.602 * 10^-19 Coulombs
For an ionized atom, the net charge is equal to the sum of charges in the proton and the electron in that atom.
From the question, we are told that, the iron atom has 26 protons and 7 electrons.
The net charge Q = 26 [ +e] + 7 [- e] = +19 e
+19 e = + 19 [1.602 * 10^-19 C] = + 3.04 * 10^-18 C.


3 0
3 years ago
. Nhiệt độ ban đầu của 344 g một mẫu sắt là 18,2oC. Nếu mẫu sắt này hấp thụ 2,25 kJ nhiệt lượng thì nhiệt độ cuối của mẫu sắt nà
Mrrafil [7]

Answer:

ano poh paki ult kasi hindi mahintindihan yan question mo hindi mahintindihwn

8 0
3 years ago
Read 2 more answers
Why is graphite used instead of gold or copper wires to conduct electricity in very hot situations such as an industrial kiln?
Molodets [167]
It wont melt like gold and copper would at that temperature

4 0
4 years ago
Read 2 more answers
A 825 g iron block is heated to 352 degrees C and is placed in an insulated container (of negligible heat capacity) containing 4
Stella [2.4K]

Answer : The final equilibrium temperature of the water and iron is, 537.12 K

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of iron =  560 J/(kg.K)

c_1 = specific heat of water = 4186 J/(kg.K)

m_1 = mass of iron = 825 g

m_2 = mass of water = 40 g

T_f = final temperature of water and iron = ?

T_1 = initial temperature of iron = 352^oC=273+352=625K

T_2 = initial temperature of water = 20^oC=273+20=293K

Now put all the given values in the above formula, we get:

(825\times 10^{-3}kg)\times 560J/(kg.K)\times (T_f-625K)=-(40\times 10^{-3}kg)\times 4186J/(kg.K)\times (T_f-293K)

T_f=537.12K

Therefore, the final equilibrium temperature of the water and iron is, 537.12 K

8 0
3 years ago
How many milliliters of 0.121 M HCl are needed to neutralize 44.3 mL 0.274 M Ba(OH)2? Write the equation and don't forget to bal
Sergeeva-Olga [200]

Answer:

100 mL is the volume of HCl needed to neutralize the 44.3 of Ba(OH)₂

Explanation:

This is the chemical equation:

2HCl + Ba(OH)₂  →  BaCl₂ + 2H₂O

Formula for neutralization is:

Molarity of acid . Volume of acid = Molarity of base . Volume of base

0.121 . Volume of acid = 0.274 . 44.3

Volume of acid = (0.274 . 44.3) / 0.121 → 100

6 0
3 years ago
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