The statement that best describes an advantage of cloning is that it can prevent genetic diseases. DNA cloning is a term used in recombinant DNA technology happens when a DNA strand belonging to one organism is transmitted into a particular type of genetic element having the capacity to self replicate. DNA cloning was developed to offer solutions related to healthcare and medical issues. Illnesses occur mostly because our body fails to produce essential proteins in ample amount is needed, these problems and other inherited problems may be solved using DNA cloning.
Answer:
0.544 M
Explanation:
First find the moles in the final solution
0.8 mols/L *1.7L
1.36 mols
so there is 1.36 mols in 2.5L
concentration will be 1.36/2.5
0.544 M
Answer:
Oxygen.
Explanation:
Oxygen is a chemical element that aides in the burning of materials and it is needed for humans to breathe.
Cellular respiration can be defined as a series of metabolic reactions that typically occur in cells so as to produce energy in the form of adenosine triphosphate (ATP). During cellular respiration, high energy intermediates are created that can then be oxidized to make adenosine triphosphate (ATP). Therefore, the intermediary products are produced at the glycolysis and citric acid cycle stage through the breathing of oxygen used to obtain energy from the food ingested.
Hence, all cells in living organisms require oxygen and glucose to release energy.
Answer:
43.75 g of Nitrogen
Explanation:
We'll begin by calculating the mass of 1 mole of NH₄NO₃. This can be obtained as follow:
Mole of NH₄NO₃ = 1 mole
Molar mass of NH₄NO₃ = 14 + (4×1) + 14 + (3×16)
= 14 + 4 + 14 + 48
= 80 g/mol
Mass of NH₄NO₃ =?
Mass = mole × molar mass
Mass of NH₄NO₃ = 1 × 80 = 80 g
Next, we shall determine the mass of N in 1 mole of NH₄NO₃.
Mass of N in NH₄NO₃ = 2N
= 2 × 14
= 28 g
Thus,
80 g of NH₄NO₃ contains 28 g of N.
Finally, we shall determine the mass of N in 125 g of NH₄NO₃. This can be obtained as follow:
80 g of NH₄NO₃ contains 28 g of N.
Therefore, 125 g of NH₄NO₃ will contain = (125 × 28) / 80 = 43.75 g of N.
Thus, 125 g of NH₄NO₃ contains 43.75 g of Nitrogen
