what is the force on a 1,000 kilogram elevator that is falling freely under the acceleration of gravity only
1 answer:
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Answer:
Elevation =31.85[m]
Explanation:
We can solve this problem by using the principle of energy conservation. This consists of transforming kinetic energy into potential energy or vice versa. For this specific case is the transformation of kinetic energy to potential energy.
We need to first identify all the input data, and establish a condition or a point where the potential energy is zero.
The point where the ball is thrown shall be taken as a reference point of potential energy.
m = mass of the ball = 300 [gr] = 0.3 [kg]
v = initial velocity = 25 [m/s]
Answer:
The slope of a position-time graph can be calculated as:
where
is the increment in the y-variable
is the increment in the x-variable
We can verify that the slope of this graph is actually equal to the velocity. In fact:
corresponds to the change in position, so it is the displacement,
corresponds to the change in time
, so the time interval
Therefore the slope of the graph is equal to
which corresponds to the definition of velocity.