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3 years ago

what is the force on a 1,000 kilogram elevator that is falling freely under the acceleration of gravity only

1 answer:

4 0

Force is equal to weight, F= ma acceleration "a", is now due to gravity g = 9.8 m/s²

Given: Mass m = 1,000 Kg

F =ma W = mg = (1,000 Kg)(9.8 m/s²)

F = 9,800 N

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How original were Newton’s contributions to science? (In what ways did Newton depend on the mechanical view?)

kvasek [131]

Newton's new “reflecting telescope” was more powerful than ... Before Newton, scientists primarily adhered to ancient theories on ... laws of motion laid the groundwork for classical mechanics. Newton's research on motion helped give credibility to the heliocentric view. Newton also helped pioneer telescopic innovations, and he is sometimes credited with inventing the first reflecting telescope. He also conducted experiments using the prism, and developed a theory about the nature of color and light.

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3 years ago

Express the kinetic energy K in terms of the potential energy U.<br><br><br> K=GMm/2R

max2010maxim [7]

Answer:

K = -½U

Explanation:

From Newton's law of gravitation, the formula for gravitational potential energy is;

U = -GMm/R

Where,

G is gravitational constant

M and m are the two masses exerting the forces

R is the distance between the two objects

Now, in the question, we are given that kinetic energy is;

K = GMm/2R

Re-rranging, we have;

K = ½(GMm/R)

Comparing the equation of kinetic energy to that of potential energy, we can derive that gravitational kinetic energy can be expressed in terms of potential energy as;

K = -½U

7 0

3 years ago

15. If an 800.-kg sports car slows to 13.0 m/s to check out an accident scene and the

goldfiish [28.3K]

The final combined velocity after the collision is 20.2 m/s

Explanation:

We can solve this problem by using the law of conservation of momentum: in fact, in absence of external forces, the total momentum of the two car and of the truck must be conserved before and after the collision.

This means that we can write the following equation:

$p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1+m_2)v$

where:

$m_1 = 800 kg$ is the mass of the sport car

$u_1 = 13.0 m/s$ is the initial velocity of the car (taking its direction as positive direction)

$m_2 = 1200 kg$ is the mass of the truck

$u_2 = 25.0 m/s$ is the initial velocity of the truck

$v$ is the final combined velocity of the car and the truck, after the collision

Re-arranging the equation and substituting the values, we find the velocity after the collision:

$v=\frac{m_1 u_1 + m_2 u_2}{m_1+m_2}=\frac{(800)(13)+(1200)(25)}{800+1200}=20.2 m/s$

And the positive sign indicates their final direction is the same as the initial direction of the two vehicles.

Learn more about momentum here:

brainly.com/question/7973509

brainly.com/question/6573742

brainly.com/question/2370982

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#LearnwithBrainly

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3 years ago

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rodikova [14]

Answer:

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Explanation:

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4 0

3 years ago

The gamma ray released by each decay carries 140kev of energy. find the total energy e released by decays in the 2 hours.

olya-2409 [2.1K]

First, we would need to know the decaying isotope.
Next, we use the decay formula
A = Ao e^(-kt)
After determining the remaining amount after two hours, the decay reaction can be used to determine the number of gamma rays released. If the given is in terms of mole, then the total energy is
E = 140n KeV where n is the number of moles of gamma rays released

8 0

3 years ago

Read 2 more answers