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IrinaK [193]
2 years ago
12

PLEASE HELP! I NEED TO ANSWER THIS QUICKLY!

Physics
1 answer:
rodikova [14]2 years ago
4 0

Answer:

I'm not a genius ok?

Explanation:

1. Radar communication, Analysis of the molecular and atomic structure, telephone communication

2. c

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How long does it take the Sun to melt a block of ice at 0∘C with a flat horizontal area 1.0 m2 and thickness 2.0 cm ? Assume tha
sineoko [7]

Answer:

It takes <em>40 hours</em> to melt the block of ice.

Explanation:

According to the principles of radiation and heat transfer respectively:

<em>ΔQ = I(dt)eAcosθ  </em>(I = Solar energy density; dt = time taken; e = emissivity; A = Area of block; θ = angle between the sun ray and the horizontal)

<em>ΔQ = mLf</em>  (ΔQ = Heat change; m = mass of ice; Lf = Specific latent heat of fusion of ice)

but m = ρV = ρ.A.<em>d</em>x, therefore, the heat transfer equation can be re-written as:

<em>ΔQ = ρ.A.dx.Lf</em>

Lets equate the radiation equation and the modified heat transfer equation, we have:

<em>ρ.A.dx.Lf = I(dt)eAcosθ</em>

<em>ρ.dx.Lf = I(dt)ecosθ    </em>(Striking out the area)

Let's make <em>dt</em> the subject of formula,

dt = ρ.dx.Lf /I.e.cosθ

ρ = Density of ice, 9.2x10^{2} Kg/m^{3}

Lf = 3.36x10^{5} J/Kg

e = 0.050

θ = 32 deg. C

Now, let's substitute the terms:

dt=\frac{(9.2x10^{2})(0.02)(3.36x10^{5} ) }{(1000)(0.050)(cos32)}

dt=14.45x10^{4} s = \frac{14.45x10^{4}}{3600} hr=40.14 hr

Therefore, the time taken for the ice to completely melt is <em>40 hours</em> (Two significant figures)

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3 years ago
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yawa3891 [41]

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