Answer:
The magnitude of magnetic field at given point = × T
Explanation:
Given :
Current passing through both wires = 5.0 A
Separation between both wires = 8.0 cm
We have to find magnetic field at a point which is 5 cm from any of wires.
From biot savert law,
We know the magnetic field due to long parallel wires.
⇒
Where magnetic field due to long wires, , perpendicular distance from wire to given point
From any one wire 5 cm, 3 cm
so we write,
∴
Therefore, the magnitude of magnetic field at given point =
Answer:
780 m to travel north
Explanation:
6 m over = 750
53 degree so it will take about 2 min to reach the destination
V^2=u^2 +2aS
U is found first by considering that first 8 secs and using v=u+at. {different v and u though}
V=-u+gt.
Magnitude of u = magnitude of v if there is no resistance ( because the conservation of energy says the k. E. must be the same when it passes you as when it left your hand).... up is negative here, down is positive.
V+v=gt
2v= g x 8
V=4xg.= the initial velocity for the next calculation
V^2=(4g)^2+(2xgx21)
So v can be calculated.