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3 years ago

Which type of clouds are feathery,high in the sky,and are made mostly of ice crystals?

Chemistry

2 answers:

german3 years ago

6 0

Hello!

1.) "Cirrus" would be the right choice.

Hope this helps! :)

Temka [501]3 years ago

5 0

The cloud with those characteristics is #1

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a concentration solution of H2so4 is 59.4% by mass (m/m) and has a density of 1.83 g/mL. How many mL of the solution would be re

Blababa [14]

Answer: 41.5 mL

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

$Molarity=\frac{n}{V_s}$

where,

n = moles of solute

$V_s$ = volume of solution in L

Given : 59.4 g of $H_2SO_4$ in 100 g of solution

moles of $H_2SO_4=\frac{\text {given mass}}{\text {molar mass}}=\frac{59.4g}{98g/mol}=0.61$

Volume of solution = $\frac{\text {mass of solution}}{\text {density of solution}}=\frac{100g}{1.83g/ml}=54.6ml$

Now put all the given values in the formula of molality, we get

$Molality=\frac{0.61\times 1000}{54.6ml}=11.2M$

To calculate the volume of acid, we use the equation given by neutralisation reaction:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of stock acid which is $H_2SO_4$

$M_2\text{ and }V_2$ are the molarity and volume of dilute acid which is $H_2SO_4$

We are given:

$M_1=11.2M\\V_1=mL\\M_2=0.30M\\V_2=1550mL$

Putting values in above equation, we get:

$11.2\times V_1=0.30\times 1550\\\\V_1=41.5mL$

Thus 41.5 mL of the solution would be required to prepare 1550 mL of a .30M solution of the acid

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3 years ago

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HORMONES ARE CHEMICAL SUBSTANCES SECRETED BY GLANDS

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3 years ago

What is the molarity of a solution that contains 14 moles of solute and 2 liters of solution?

Nata [24]

Answer:

7 M

Explanation:

The molarity is defined as "moles per liter." Here, it is ...

(14 moles)/(2 liters) = 7 moles/liter = 7 M

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Which acid and base react in the formation of salt sodium chloride? hydrochloric acid and sodium hydroxide sodium carbonate and

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Hydrochloric acid and sodium hydroxide

HCl + NaOh ----> NaCl + H2O

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