Cookies would not be an effective pre-exercise energizing snack, as their high sugar content would be absorbed quickly by the body, not sustaining the athlete for the duration of their event.
The time taken by the runner to do the work is 1.42 seconds.
Given the data in the question;
- Work done;

- Power;

- Time elapsed;

<h3>Power</h3>
Power can be simply referred to as the quantity of energy transferred per unit time.
It is expressed as;

Where W is work done and t is time elapsed.
To determine the time it took the runner to do the work, we substitute our given values into the expression above.

Therefore, the time taken by the runner to do the work is 1.42 seconds.
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Answer:
warmed should be ur answer
Explanation:
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Answer:
The velocity of the student has after throwing the book is 0.0345 m/s.
Explanation:
Given that,
Mass of book =1.25 kg
Combined mass = 112 kg
Velocity of book = 3.61 m/s
Angle = 31°
We need to calculate the magnitude of the velocity of the student has after throwing the book
Using conservation of momentum along horizontal direction


Put the value into the formula


Hence, The velocity of the student has after throwing the book is 0.0345 m/s.
Answer:
Jim's kinetic energy is 54.67 J.
Explanation:
Given that,
Mass, m = 15 kg
Velocity, V = 2.7 m/s
We need to find the Jim's kinetic energy. We know that when the object is in motion, it has kinetic energy. This energy is given by :


E = 54.67 J
So, Jim's kinetic energy is 54.67 J. Hence, this is the required solution.