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JulijaS [17]
3 years ago
9

A 30.9 kg rocket has an engine

Physics
1 answer:
Verizon [17]3 years ago
5 0

Answer:

acceleration = 15.8 m/s^2

Explanation:

Weight of rocket which acts downward is W = mass × acceleration due to gravity

w = 30.9 × 9.81

W = 303.129 N

force of 790 N acts upward and it is greater than W hence acceleration is in upward direction and is given by Newton's second law of motion as

790 - W = mass × acceleration

790 - 303.129 = 30.9 × acceleration

486.871  = 30.9 × acceleration

acceleration = 486.871 / 30.9

acceleration = 15.756 m/s^2

acceleration = 15.8 m/s^2

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If the torque required to loosen a nut that is holding a flat tire in place on a car has a magnitude of 41 N · m, what minimum f
Marina86 [1]

We have that the Force  is mathematically given as

F=170.833N

<h3></h3><h3>Force </h3>

Question Parameters:

  • The torque required to loosen a nut that is holding a flat tire in place on a car has a magnitude of 41 N · m,
  • the end of a 24 cm-long  wrench to <em>loosen </em>the nut

Generally the equation for the Force   is mathematically given as

F=\frac{T}{d}

Therefore

F=41/0.24

F=170.833N

For more information on Force visit

brainly.com/question/26115859

3 0
2 years ago
Calculating Velocity
m_a_m_a [10]

The average velocity of the object represented by the  distance time graph is 0.1\:meter\:per\:second

  • The velocity of an object is the change in the distance moved by an object with time.

  • This could also be related to the rate of change or slope of the graph.

  • Average velocity = \frac{change\:in\:distance}{change\:in\:time}

  • Average velocity = \frac{(5-0)}{(50-0}) = \frac{5}{50}=0.1\:meter\:per\:second

Therefore, the average velocity of the object is 0.1\:meter\:per\:second

Learn more :brainly.com/question/1378025

5 0
3 years ago
A weak magnet can become stronger by dropping it or striking it with a hammer.<br> True Or False
Vikentia [17]
I think it is false, because why would is be stronger in a different state?

4 0
3 years ago
You carry a 7.0-kg bag of groceries 1.2 m above the ground at constant speed across a 2.7m room. How much work do you do on the
ELEN [110]

Answer:

Work done, W = 0 J

Explanation:

It is given that,

Mass of the bag, m = 7 kg

If a person carries a bag of groceries 1.2 m above the ground at constant speed across a 2.7 m room. We need to find the amount of work done on the bag he the process. It is given by :

W=Fd\ cos\theta

Where

θ = angle between the force and the direction of motion. Here, θ = 90° (its weight is acting vertically downward and it is moving forward)

Since, cos(90) = 0

⇒ Work done, W = 0 J

So, the work done on the bag is zero. Hence, the correct option is (b) "0 J".

3 0
3 years ago
3kg of water at 80degree celcius is added to 8 kg of water at 25 degree celcius. find the temperature of final mixture provided
Nitella [24]

Answer:

hope fully it help s

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3 years ago
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