Answer:
B) K⁺, Sr²⁺ , O²⁻
Explanation:
Potassium is present in group one. It is alkali metal and have one valance electron.Potassium need to lose its one valance electron and form cation to get complete octet.
That's why it shows K⁺.
Sr is alkaline earth metal. It is present in group two. It has two valance electrons. Strontium needed to lose its two valance electrons and get stable electronic configuration.
When it loses its two valance electrons it shows cation with charge of +2.
Sr²⁺
Oxygen is present in group 16. It has sex valance electrons. It needed two more electrons to complete the octet. That's why oxygen gain two electron and form anion with a charge of -2.
O²⁻
Answer:
"ite"
Explanation:
Se sabe que los elementos del grupo 16 de la tabla prioritaria muestran estados de oxidación o valencias de 2,4 y 6 respectivamente, dependiendo del compuesto formado.
Por ejemplo, el azufre forma los siguientes compuestos;
sulfato de sodio (el azufre tiene una valencia de 6)
Sulfito de sodio (el azufre tiene una valencia de 4)
Sulfuro de sodio (el azufre tiene una valencia de 2)
Por lo tanto, en compuestos en los que exhiben una valencia de 4, la terminación común es "ite"
Answer:
the volume of the gas will decrease
That would be the NOBLE GASES (Helium, Neon, Argon, Krypton, Xenon, Radon). Because these elements have a filled outer shell (thus giving them the full octet that other elements crave), they are stable elements under normal circumstances and as such resist chemical combination.
Plz note that under special conditions, noble gases such as Xenon and Radon can form compounds (Xenon Fluoride and Oxide; Radon Fluoride)
i think 12000 is the answer