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Inessa05 [86]
3 years ago
10

A bicycle traveled 150 meters west from point A to point B. Then It took the same route and came back to point A. It took a tota

l of 2 minutes for
the bicycle to return to point A. What is the average speed and average velocity of the bicycle?
A.
The average speed is 2.5 meters/second, and the average velocity is
2.5 meters/second east.
B.
The average speed Is 0 meters/second, and the average velocity is
2.5 meters/second east.
C. The average speed and average velocity are both 0 meters/second.
D.
The average speed is 2.5 meters/second, and the average velocity is
O meters/second.
Physics
1 answer:
Julli [10]3 years ago
6 0

Answer:

Option D.  The average speed is 2.5 meters/second, and the average velocity is  0 meters/second.

Explanation:

we know that

To find out the average speed divide the total distance by the total time

Let

d -----> the total distance in meters

t -----> the time in seconds

s ----> the speed in meters per second

s=\frac{d}{t}

Remember that

1\ min=60\ sec

we have

t=2\ min=2(60)=120\ sec

d=150(2)=300\ m

substitute

s=\frac{300}{120}

s=2.5\frac{m}{sec}

<u><em>Find out the average velocity</em></u>

To find out the average velocity divide the displacement) by the time

The displacement is the distance from the start point to the end point regardless of the route

In this problem

The start point is A and the end point is A

so

The displacement  is equal to zero

therefore

The average velocity is 0 m/sec

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Answer:

13.4cm

Explanation:

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The fast train known as the TGV (Train à Grande Vitesse) that runs south from Paris, France, has a scheduled average speed of 21
andrezito [222]

Answer:

Explanation:

Given

average speed of train(v_{avg})=216 kmph\approx 60 m/s

Maximum acceleration=0.05g

Now centripetal acceleration is

a_c=\frac{v^2}{r}

0.05\times 9.8=\frac{60^2}{r}

r=7346.93 m

(b)Radius of curvature=900 m

therefore a_c=\frac{v^2}{r}

v=\sqrt{a_cr}

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8 0
3 years ago
A major-league pitcher can throw a ball in excess of 40.1 m/s. If a ball is thrown horizontally at this speed, how much will it
mote1985 [20]

Answer:

The ball will drop 0.881 m by the time it reaches the catcher.

Explanation:

The position of the ball at time "t" is described by the position vector "r":

r = (x0 + v0x · t, y0 + v0y · t + 1/2 · g · t²)

Where:

x0 = initial horizontal position.

v0x = initial horizontal velocity.

t = time.

y0 = initial vertical position.

v0y = initial vertical velocity.

g = acceleration due to gravity (-9.8 m/s² considering the upward direction as positive).

When the ball reaches the catcher, the position vector will be "r final" (see attached figure).

The x-component of the vector "r final", "rx final", will be 17.0 m. We have to find the y-component.

Using the equation of the x-component of the position vector, we can calculate the time it takes the ball to reach the catcher (notice that the frame of reference is located at the throwing point so that x0 and y0 = 0):

x = x0 + v0x · t

17.0 m = 0 m + 40.1 m/s · t

t = 17.0 m/ 40. 1 m/s = 0.424 s

With this time, we can calculate the y-component of the vector "r final", the drop of the ball:

y = y0 + v0y · t + 1/2 · g · t²

Initially, there is no vertical velocity, then, v0y = 0.

y = 1/2 · g · t²

y = -1/2 · 9.8 m/s² · (0.424 s)²

y = -0.881 m

The ball will drop 0.881 m by the time it reaches the catcher.

8 0
3 years ago
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