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Inessa05 [86]
3 years ago
10

A bicycle traveled 150 meters west from point A to point B. Then It took the same route and came back to point A. It took a tota

l of 2 minutes for
the bicycle to return to point A. What is the average speed and average velocity of the bicycle?
A.
The average speed is 2.5 meters/second, and the average velocity is
2.5 meters/second east.
B.
The average speed Is 0 meters/second, and the average velocity is
2.5 meters/second east.
C. The average speed and average velocity are both 0 meters/second.
D.
The average speed is 2.5 meters/second, and the average velocity is
O meters/second.
Physics
1 answer:
Julli [10]3 years ago
6 0

Answer:

Option D.  The average speed is 2.5 meters/second, and the average velocity is  0 meters/second.

Explanation:

we know that

To find out the average speed divide the total distance by the total time

Let

d -----> the total distance in meters

t -----> the time in seconds

s ----> the speed in meters per second

s=\frac{d}{t}

Remember that

1\ min=60\ sec

we have

t=2\ min=2(60)=120\ sec

d=150(2)=300\ m

substitute

s=\frac{300}{120}

s=2.5\frac{m}{sec}

<u><em>Find out the average velocity</em></u>

To find out the average velocity divide the displacement) by the time

The displacement is the distance from the start point to the end point regardless of the route

In this problem

The start point is A and the end point is A

so

The displacement  is equal to zero

therefore

The average velocity is 0 m/sec

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lapo4ka [179]

Answer:

8.72*10^{-12} N

Explanation:

force of attraction f = G m1m2/ r^2 = \frac{6.67*10^{-11}*7*5*2.70 }{.85*.85*1000} = 8.72*10^{-12} N

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The sound intensity level from one solo flute is 70 dB. If 10 flutists standing close together play in unison, what will the sou
Masja [62]

Answer:

80 dB

Explanation:

I_0 = Threshold intensity = 10^{-12}\ W/m^2

I = Intensity of sound

\beta = Intensity level of sound = 70 dB

Intensity level of sound is given by

\beta=10log\dfrac{I}{I_0}\\\Rightarrow 70=10log\dfrac{I}{I_0}\\\Rightarrow \dfrac{70}{10}=log\dfrac{I}{10^{-12}}\\\Rightarrow 10^{\dfrac{70}{10}}=\dfrac{I}{10^{-12}}\\\Rightarrow \dfrac{I}{10^{-12}}=10^{\dfrac{70}{10}}\\\Rightarrow I=10^{7}\times 10^{-12}\\\Rightarrow I=10^{-5}\ W/m^2

If there are 10 flutes I=10\times 10^{-5}\ W/m^2

\beta=10log\dfrac{10\times 10^{-5}}{10^{-12}}\\\Rightarrow \beta=10log10^8\\\Rightarrow \beta=10\times 8\\\Rightarrow \beta=80\ dB

The sound intensity level is 80 dB

5 0
3 years ago
What is the SI unit of electric charge
shusha [124]

Answer:

The SI unit for electric chargeis the C (which is the abbreviation of Coulomb}

Explanation:

The SI unit for electric chargeis the Coulomb. The letter used is the C.

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4 0
3 years ago
A capacitor is connected to an ac generator that has a frequency of 2.3 kHz and produces a rms voltage of 1.5 V. The rms current
miv72 [106K]

Answer:

Explanation:

Given that,

AC frequency of 2.3KHz

f=2.3×10³Hz

Vrms produce is

Vrms=1.5V

Current rms

Irms= 31mA

The capacitor is reconnected to a generator of frequency

f=4.8KHz =4800Hz

The current rms becomes

Irms= 85mA

Vrms=?

Solution

First genrator

The capacitive reactance is given as

Xc=Vrms/Irms

Xc=1.5/31×10^-3

Xc=48.39 ohms

Now, to know the capacitance of the capacitor

Xc=1/2πfC

Then,

C=1/2πfXc

So,

C=1/2×π×2300×48.39

C=1.43×10^-6C

C=1.43μF

Note: the capacitance of the capacitor did not change,

Now for generator two.

The reactance are given as

Xc=1/2πfC

Xc=1/2×π×4800×1.43×10^-6

Xc=23.19ohms

Then,

Vrms2=Irms2 ×Xc

Vrms2=85×10^-3×23.19ohms

Vrms2=1.97V

Vrms2=1.97Volts

7 0
3 years ago
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