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disa [49]
3 years ago
13

There are two tuning forks struck at the same time. One tuning fork is tuned to a frequency note of 500 Hz. The other is tuned t

o a frequency of 487 Hz. How many beats will occur in 2 seconds?
Physics
1 answer:
fomenos3 years ago
6 0

Answer: 26 beats in 2 seconds

Explanation:

The number of beats per second = frequency of tuning fork 1 - frequency of tuning fork 2.

Given :

- frequency of tuning fork 1 = 500Hz

- frequency of tuning fork 2 = 487Hz

Thus,

Beats per second = 500 - 487

= 13 beats per second

Therefore in two(2) seconds, you will have 2 x 13 = 26 seconds.

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A student who runs every day is becoming bored with her physical fitness routine and considers quitting. What is the most effect
LiRa [457]

Answer:

Explained

Explanation:

A student who runs every day is becoming bored with her physical fitness routine and considers quitting. Now in order maintain her fitness routine she needs to break the monotony by changing her exercise regime. She do other activities like play sports two days a week, she do aerobics, she even try some cardio vascular exercises which as good as running. She also try changing her route of running as the new view might inspire her.

8 0
3 years ago
What is the maximum number of orbitals in the p sublevel?
dedylja [7]

Answer:

3 orbitals

Explanation:

The p sublevel can carry a maximum of 6 electrons. Therefore it must be made of 3 orbitals which each, as in any orbital of any other sublevel, can carry 2 electrons. So there is a p sub x orbital, p sub y orbital and p sub z orbital which are all orthogonal to each other.  

7 0
3 years ago
A cheetah can accelerate at 4.5 m/s from rest to a speed of 30.0 m/s. Calculatethe distance
anzhelika [568]

Answer:

d= 100m

Explanation:

Cheetah kinematic

The cheetah moves with uniformly accelerated movement, and the formulas that describe this movement are:

d= v₀*t + (1/2)*a*t²  Formula (1)

vf²=v₀²+2*a*d Formula (2)

vf=v₀+a*t  Formula (3)

Where:

d:distance in meters (m)  

v₀: initial speed in m/s  

vf: final speed in m/s  

a: acceleration in m/s²  

t: time in seconds (s)

Known Data

v₀ =0

a =  4.5 m/s²

vf= 30 m/s.

Problem development

We apply the formula (2) that has known data to calculate the distance :

vf²=v₀²+2*a*d

(30)²= 0 + 2*  4.5* d

d= \frac{900}{9}

d= 100m

8 0
3 years ago
Define what an astronomical unit is and explain why it is used.
Ivahew [28]

Answer:

AU

Explanation:

Astronomical units are used to measure the  distances within solar system

5 0
3 years ago
Read 2 more answers
A 4 kilogram (kg) toy car accelerates from 3.0 meters per second (m/s) to 8.0 meters per second. What is the change in the cart'
zysi [14]

Answer:

20 kg*m/s

Explanation:

we're looking for the change in the cars momentum . the formula to identify the cars momentum is Δp=m*vf-m*vi . In this case m= mass , vf= velocity final, and vi= velocity initial . The mass is how much the car weighs , which is 4 kg . Velocity final would be 8 m/s since that's how fast it last was . Velocity initial would be 3 m/s since it had first started at that speed . Now we can jus plug it into the formula .

m= 4 kg

vf= 8 m/s

vi= 3 m/s

Δp= (4)*(8) - (4)*(3)

Δp= 32-12

Δp= 20 kg*m/s

hope this helps .

5 0
3 years ago
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