F=ma so a=F/m
ax=180/270=0.67m/s^2
ay=390/270=1.44m/s^2
Magnitude = sqrt((0.67^2)+(1.44^2))=1.59m/s^2
Direction- Tan(x)=0.67/1.44=0.47 Tan^-1(x)=25 degrees
Answer:
<h3>
The coefficient of kinetic friction between the puck and the ice is 
0.12</h3>
Explanation:
Given :
Initial speed 
Displacement 
m
From the kinematics equation,
Where 
final velocity, in our example it is zero (
), 
acceleration.
From the formula of friction,
Minus sign represent friction is oppose the motion
Where 
( normal reaction force )
( ∵ 
)
So coefficient of friction,
Therefore, the coefficient of kinetic friction between the puck and the ice is 0.12 .
Ionic bonds are formed between a cation (metal) and an anion (nonmetal)
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