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deff fn [24]
3 years ago
12

Which statement describes one feature of Rutherford's model of the atom?

Physics
1 answer:
Arlecino [84]3 years ago
7 0

Answer:

The atom is mostly empty space.

Explanation:

Ernest Rutherford in the year 1911 developed a model of an atom. In his model the atom was shown that the atom is mostly empty spaces composed of negative electrons which orbits round a positive nucleus just like planets revolving round the sun.

Rutherford came up with this model by performing experiments in 1909 which involves the scattering of alpha particles on a thin gold foil. From this experiments he came up with his model.

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A wave with a frequency of 1200 Hz propagates along a wire that is under a tension of 800 N. Its wavelength is 39.1 cm. What wil
mash [69]

Answer:

The wavelength will be 33.9 cm

Explanation:

Given;

frequency of the wave, F = 1200 Hz

Tension on the wire, T = 800 N

wavelength, λ = 39.1 cm

F = \frac{ \sqrt{\frac{T}{\mu} }}{\lambda}

Where;

F is the frequency of the wave

T is tension on the string

μ is mass per unit length of the string

λ is wavelength

\sqrt{\frac{T}{\mu} } = F \lambda\\\\\frac{T}{\mu} = F^2\lambda^2\\\\\mu =  \frac{T}{F^2\lambda^2} \\\\\frac{T_1}{F^2\lambda _1^2} = \frac{T_2}{F^2\lambda _2^2} \\\\\frac{T_1}{\lambda _1^2} = \frac{T_2}{\lambda _2^2}\\\\T_1 \lambda _2^2 = T_2\lambda _1^2\\\\

when the tension is decreased to 600 N, that is T₂ = 600 N

T_1 \lambda _2^2 = T_2\lambda _1^2\\\\\lambda _2^2  = \frac{T_2\lambda _1^2}{T_1} \\\\\lambda _2 = \sqrt{\frac{T_2\lambda _1^2}{T_1}} \\\\\lambda _2 = \sqrt{\frac{600* 0.391^2}{800}}\\\\\lambda _2  = \sqrt{0.11466} \\\\\lambda _2  =0.339 \ m\\\\\lambda _2  =33.9  \ cm

Therefore, the wavelength will be 33.9 cm

5 0
3 years ago
Two forces act on wooden box with mass of (30kg) (if F1,=85.7N east and F270.7N west):
tresset_1 [31]

The acceleration of the wooden box is 6.17 m/s² towards the west.

<h3 /><h3>What is acceleration?</h3>

Acceleration can be defined as the rate of change of velocity.

To calculate the acceleration of the wooden box can be calculated using the formula below.

Formula:

  • F₂-F₁ = ma.................. Equation 1

Where:

  • F₂ = Force on the wooden box acting towards west
  • F₁ = Force on the wooden box acting towards the east
  • m = Mass of the wooden box.
  • a = Acceleration of the wooden box

Make a the subject of the equation

  • a = (F₂-F₁)/m........................ Equation 2

From the question,

Given:

  • F₂ = 270.7 N
  • F₁ = 85.7 N
  • m = 30 kg

Substitute these values into equation 2

  • a = (270.7-85.7)/30
  • a = 185/30
  • a = 6.17 m/s² towards the west.

Hence, The acceleration of the wooden box is 6.17 m/s² towards the west.

Learn more about acceleration here: brainly.com/question/605631


7 0
2 years ago
Two people stand facing each other at a roller skating rink then push off each other. a). What is the momentum of the system bef
Semenov [28]

Explanation:

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8 0
2 years ago
Why is there a difference between potential and kinetic energy?
inn [45]

Potential energy is stored energy because it has the potential to do something which laters turns into kinetic energy which is the moving energy.

3 0
2 years ago
a hammer of mass 5 kg travelling at 4 metre per second is a nail directly and does not rebound what is the impulse of the hammer
dmitriy555 [2]
20 kg.m/s
p =m*v = 5*4 = 20
5 0
3 years ago
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