A
<u>Individual lipid molecules are free to diffuse laterally in the surface of the bilayer</u> is a general feature of the lipid bilayer in all biological membranes
Explanation:
The inside of the bilipid layer of the cell membrane of cells is made of fatty acid chains and cholesterol which are nonpolar molecules. they are sandwiched between the polar (glycerol) ends of the chains because they are hydrophobic and cannot interact with the ‘watery’ extracellular fluids. Non-polar molecules like lipids can easily diffuse laterally, within this lipid layers of the membrane because non-polar molecules interact well with other nonpolar molecules.
Learn More:
For more on the bilipid layers of cells check out;
brainly.com/question/2011453
brainly.com/question/1457466
brainly.com/question/2011432
brainly.com/question/7435492
#LearnWithBrainly
Answer:
(a) C5H8O2
(b) C2H2Cl2
(c) CH2
(d) CH
Explanation:
We need to find the proportion of the atoms in whole numbers. Given the percentages we can calculate the number of moles and find their proportions.
Assume 100 g and given the atomic weights the moles are calculated.
(a) C = 59.9/ 12.01 = 4.98 ≈ 5.00
H = 8.06/1.007 = 8.00
O = 32/15.999 = 2.00
C5H8O2
(b) C= 24.8/12.01 = 2.06≈ 2.00
H = 2.0/1.007 = 1.99 ≈ 2.00
Cl = 73.1/ 35.453 = 2.06 ≈ 2.00
C2H2Cl2
(c) C = 86/12.01 = 7.16
H= 14/1.007 = 13.90
7.16:13.90 ≈ 1:2
CH2
(d) C = 92.30/12.01 = 7.68
H = 7.7 / 1.007 = 7.65
7.68:7.65 ≈ 1:1
CH
Each of the Isotopic mass * its Abundance Sum together divide by 100.
(179.946706*0.12 + 181.948206*26.5 + 182.9502245*14.3 + 183.9509326*30.64 + 185.954362*28.43 ) / 100
You get 183.84 (5s.f. ) or (183.8417786)
_award brainliest if helped!
Answer:
So, one mole of NaCl weighs 58.44 g. A 2.5 M solution is 2.5 moles per liter (Molarity is just the number of moles per liter). Therefore, 0.5 L would contain 1.25 mo
It depend on the optical density of an object