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True [87]
3 years ago
8

Use the titration results to calculate the moles of h2so4

Chemistry
1 answer:
Aloiza [94]3 years ago
4 0
Missing in your question: the molarity of H2SO4 M = 0.1 M
and the equivalence point (mL) = 19.31 mL = 0.019 L
So by using the molarity formula:

molarity of H2SO4 = no of moles of H2SO4 / Volume L

So by substitution:
0.1 M = no of moles of H2SO4  /  0.019 L
∴ no of moles of H2SO4 = 0.1 M * 0.019 L
                                          = 0.0019 mol
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A chemist has to prepare 250.0 mL of a 0.300 M Na2SO4(aq) solution. What mass, in grams, of sodium sulfate (formula mass 142.05
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The mass of sodium sulphate, Na₂SO₄, required to prepare the solution is 10.65 g

<h3>How to determine the mole of sodium sulphate Na₂SO₄</h3>
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  • Molarity = 0.3 M
  • Mole of Na₂SO₄ =?

Mole = Molarity x Volume

Mole of Na₂SO₄ = 0.3 × 0.25

Mole of Na₂SO₄ = 0.075 mole

<h3>How to determine the mass of sodium sulphate Na₂SO₄</h3>
  • Molar mass of Na₂SO₄ = 142.05 g/mol
  • Mole of Na₂SO₄ = 0.075 mole
  • Mass of Na₂SO₄ =?

Mass = mole × molar mass

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Learn more about molarity:

brainly.com/question/15370276

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