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3 years ago

Use the titration results to calculate the moles of h2so4

1 answer:

4 0

Missing in your question: the molarity of H2SO4 M = 0.1 M
and the equivalence point (mL) = 19.31 mL = 0.019 L
So by using the molarity formula:

molarity of H2SO4 = no of moles of H2SO4 / Volume L

So by substitution:
0.1 M = no of moles of H2SO4 / 0.019 L
∴ no of moles of H2SO4 = 0.1 M * 0.019 L
= 0.0019 mol

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Calculate the volume in milliliters of a 1.3M zinc nitrate solution that contains 100.g of zinc nitrate ZnNO32. Be sure your ans

zheka24 [161]

Answer:

The volume is 406 mL

Explanation:

Step 1: Data given

Molarity of a zinc nitrate solution = 1.3 M

Mass of zinc nitrate = 100 grams

Molar mass of Zn(NO3)2 = 189.36 g/mol

Step 2: Calculate moles Zn(NO3)2

Moles Zn(NO3)2 = mass Zn(NO3)2 / molar mass Zn(NO3)2

Moles Zn(NO3)2 = 100.0 grams / 189.36 g/mol

Moles Zn(NO3)2 = 0.5281 moles

Step 3: Calculate volume

Molarity = moles / volume

Volume = moles / molarity

Volume = 0.5281 moles / 1.3 M

Volume = 0.406 L = 406 mL

The volume is 406 mL

3 0

4 years ago

CaC2 + 2H2O ⟶ C2H2 + Ca(OH)2 How many moles of water are needed to produce 56.8g C2H2?

pshichka [43]

Amount of moles of water is 4.36 mol

Explanation: M(C2H2) = 2·12.01 + 2·1.008 = 26.036 g/mol

Amount of substance is n= m/M= 56.8 g / 26.036 g/mol= 2.18159 mol

Water is needed 2·2.18 mol = 4.36 mol

6 0

3 years ago

If the pKa of Lysine is 5, then at a pH of 7, it is most likely going to be a) Neutral. b) Negatively charged. c) Positively cha

Sladkaya [172]

C. Positively charged

7 0

3 years ago

How do magnetic forces repel or attract? make it short and simple 25 points

stiks02 [169]

Answer:

When you place the north pole of one magnet near the south pole of another magnet, they are attracted to one another.

Explanation:

6 0

3 years ago

Read 2 more answers

If 5.57 g of Ag2O is sealed in a 75.0-mL tube filled with 760 torr of N2 gas at 28 ∘C, and the tube is heated to 310 ∘C, the Ag2

Snezhnost [94]

Answer: Total pressure = 7293.2 torr or 9.60 atm

Explanation:

Total pressure = partial pressure of nitrogen + partial pressure of oxygen

The partial pressure due to nitrogen is determined using the equation of Gay-Lussac's law: P₁/T₁=P₂/T₂

P₁ = 760 torr = 1atm, T₁ = 28∘C = (273+28)K = 301k, P₂ = ?, T₂ = 310∘C =(310+273)K = 583K

P₂ = P₁ T₂/ T₁

P₂ = 760 * 583 / 301 = 1472.03 torr

The pressure due to Oxygen gas produced is calculated thus:

Balanced equation of the decomposition of Ag₂O at s.t.p. is as follows;

2Ag₂O ----> 4Ag + O₂(g)

2 moles of Ag₂O produces 1 mole of O₂

molar mass of Ag₂O = (2*108 + 16)g = 232g/mol

molar volume of gas at s.t.p. = 22.4L

2*232g i.e. 464g of Ag₂O produces 22.4L of O₂

5.57g of Ag₂O will produce 5.57g*22.4L/464g = 0.269L or 269mL of O₂

Using the General gas equation P₁V₁/T₁=P₂V₂/T₂

P₁ = 1atm = 760 torr, V₁ = 269mL, T₁=273K, P₂ = ?, V₂= 75mL, T₂ = 583K

P₂ = P₁V₁T₂/V₂T₁

P₂ = 760*269*583 / 75*273

P₂ = 5821.17 torr

Total pressure = (1472.03 + 5821.17) torr

Total pressure = 7293.2 torr or 9.60 atm

7 0

3 years ago