Answer:
1) The exergy of destruction is approximately 456.93 kW
2) The reversible power output is approximately 5456.93 kW
Explanation:
1) The given parameters are;
P₁ = 8 MPa
T₁ = 500°C
From which we have;
s₁ = 6.727 kJ/(kg·K)
h₁ = 3399 kJ/kg
P₂ = 2 MPa
T₂ = 350°C
From which we have;
s₂ = 6.958 kJ/(kg·K)
h₂ = 3138 kJ/kg
P₃ = 2 MPa
T₃ = 500°C
From which we have;
s₃ = 7.434 kJ/(kg·K)
h₃ = 3468 kJ/kg
P₄ = 30 KPa
T₄ = 69.09 C (saturation temperature)
From which we have;
h₄ =
+ x₄×
= 289.229 + 0.97*2335.32 = 2554.49 kJ/kg
s₄ =
+ x₄×
= 0.94394 + 0.97*6.8235 ≈ 7.563 kJ/(kg·K)
The exergy of destruction,
, is given as follows;
= T₀ ×
= T₀ ×
× (s₄ + s₂ - s₁ - s₃)
= T₀ ×
×(s₄ + s₂ - s₁ - s₃)/(h₁ + h₃ - h₂ - h₄)
∴
= 298.15 × 5000 × (7.563 + 6.958 - 6.727 - 7.434)/(3399 + 3468 - 3138 - 2554.49) ≈ 456.93 kW
The exergy of destruction ≈ 456.93 kW
2) The reversible power output,
=
+
≈ 5000 + 456.93 kW = 5456.93 kW
The reversible power output ≈ 5456.93 kW.
Answer:
a bond issued by a bank or other financial institution, guaranteeing the fulfilment of a particular contract
Answer:

Explanation:
The stress experimented by the circular bar is:
![\sigma = \left[\frac{2000\, lbf}{\frac{\pi}{4}\cdot (0.5\,in)^{2}}\right]\cdot \left(\frac{1\,kpsi}{1000\,psi} \right)](https://tex.z-dn.net/?f=%5Csigma%20%3D%20%5Cleft%5B%5Cfrac%7B2000%5C%2C%20lbf%7D%7B%5Cfrac%7B%5Cpi%7D%7B4%7D%5Ccdot%20%280.5%5C%2Cin%29%5E%7B2%7D%7D%5Cright%5D%5Ccdot%20%5Cleft%28%5Cfrac%7B1%5C%2Ckpsi%7D%7B1000%5C%2Cpsi%7D%20%5Cright%29)

The safety factor is:


Answer: Partial pressures are 0.6 MPa for nitrogen gas and 0.4 MPa for carbon dioxide.
Explanation: <u>Dalton's</u> <u>Law</u> <u>of</u> <u>Partial</u> <u>Pressure</u> states when there is a mixture of gases the total pressure is the sum of the pressure of each individual gas:

The proportion of each individual gas in the total pressure is expressed in terms of <u>mole</u> <u>fraction</u>:
= moles of a gas / total number moles of gas
The rigid tank has total pressure of 1MPa.
molar mass = 14g/mol
mass in the tank = 2000g
number of moles in the tank:
= 142.85mols
molar mass = 44g/mol
mass in the tank = 4000g
number of moles in the tank:
= 90.91mols
Total number of moles: 142.85 + 90.91 = 233.76 mols
To calculate partial pressure:

For Nitrogen gas:

= 0.6
For Carbon Dioxide:



0.4
Partial pressures for N₂ and CO₂ in a rigid tank are 0.6MPa and 0.4MPa, respectively.
Answer:
Answer to both the parts A and B are provided in the word document attached.
Explanation:
The explanation of the programs is provided in the attached file along with the screenshot of ATM application output.