Option C. The object is returning to the start at a constant speed.
<h3>
Data points of the Position vs Time graph</h3>
The following data points will be used to determine the motion of the object.
<u>Position Time</u>
12 4
10 6
2 8
0 10
From the data above, the position of the object is decreasing towards zero or start point.
Thus, the object is returning to the start at a constant speed.
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1. The answer is; C
The geosphere is made up of the physical rocks (composed of metals and minerals) and magma in the different layers. These densities of these rocks surpass those of other spheres such as the atmosphere and hydrosphere.
2. The answer is; B
Destructive forces break down land. Weathering and erosion are categorized as slow destructive forces because they take many years for their effect to be perceptible to the human's scale. Quick destructive forces are forces such as earthquakes and tsunamis.
3. The answer is; B
The atmosphere on earth is mainly composed of molecular nitrogen at 78%. Oxygen takes up 21% and other gases found in the atmosphere are hydrogen, carbon dioxide,ozone, dust, and water vapor at 1%.
4. The answers that apply are ; A & B
The formula for gravity force is given by the equation.; F(gravity) = (G*m1*m2)/d^2 where G is the gravitational constant, m1 and m2 are the masses of the two objects, and d is the distance between them.
5. The answer is; C
The force of inertia is due to their celestial mass. The larger the mass the higher the inertia. Inertia is the tendency of a moving object to maintain a straight path without an external force applied to it. This, therefore, prevents the moon from being pulled into collision with the earth. Gravity, on the other hand, prevents the moon from flying out of its orbit and away into space.
Answer:
20 m/s^2
Explanation:
given,
final velocity (v) = 6000m/s
initial velocity (u) = 0m/s
time taken (t) = 5 minutes
= 5×60second
= 300second
acceleration(a) = ?
we know that,
a = (v-u)/t
= (6000-0)/300
= 20 m/s^2
The balanced equation
for the reaction is
CO(g) + 2H₂(g) ⇄ CH₃OH(g)
The given
concentrations are at equilibrium state. Hence we can use them directly in
calculation with the expression for the equilibrium constant, k.
expression for k can be written as
k = [CH₃OH(g)] / [CO(g)] [H₂<span>(g) ]²
</span>[H₂<span>]=0.072 M
[CO]= 0.020M
[CH</span>₃OH]= 0.030 M
From substitution,
k = 0.030
M / 0.020 M x (0.072 M)²
k =
289.35 M⁻²
<span>
Hence, equilibrium constant for the given reaction at 700 K is 289.35 M</span>⁻².
<span> </span>
Answer:
The half-life of the radioactive isotope is 346 years.
Explanation:
The decay rate of the isotope is modelled after the following first-order linear ordinary differential equation:
Where:
- Current isotope mass, measured in kilograms.
- Time, measured in years.
- Time constant, measured in years.
The solution of this differential equation is:
Where 
is the initial mass of the isotope. It is known that radioactive isotope decays at a yearly rate of 0.2 % annually, then, the following relationship is obtained:
The time constant associated to the decay is:
Finally, the half-life of the isotope as a function of time constant is given by the expression described below:
If , the half-life of the isotope is:
The half-life of the radioactive isotope is 346 years.
