Answer:
F = 4856.32 N
Explanation:
Given,
A satellite is orbiting earth at a distance from Earth surface, h = 35000 m
The mass of the satellite, m = 500 Kg
The radius of the Earth, R = 6.371 x 10⁶ m
The mass of the Earth, M = 5.972 x 10²⁴ Kg
The gravitational constant, G = 6.67408 x 10 ⁻¹¹ m³ kg⁻¹ s⁻²
The force between the Earth and the satellite is given by the formula
F = GMm/(R+h)² N
Substituting the values in the above equation
F = (6.67408 x 10 ⁻¹¹ X 5.972 x 10²⁴ X 500) / (6.371 x 10⁶ + 35000)²
= 4856.32 N
Hence, the force between the planet and the satellite is, F = 4856.32 N
Answer: 77 degrees
Explanation:
According to the Law of Reflection, when a ray of light strikes a surface, the angle of this ray (incident ray) with respect to the normal of the surface is equal to the angle that forms the reflected ray with the same normal of the surface.
In other words:
Both the incident ray and the reflected ray and the normal to the surface are in the same plane, in addition, the angle of the incident ray is equal to the angle of the reflected ray.
In this context, if the angle of incidence is 77 degrees, the angle of reflection is 77 degrees, as well.
I believe it is called the Greenhouse effect.
It mainly depends on the season of the year
