When water vaporizes into the air, it becomes humid out.
From Newton’s Third Law, the Law of Conservation of Momentum for an elastic collision is derived as m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂.
<h3>
Newton's third law</h3>
This law states that action and reaction are equal and opposite. That is the force applied to an object is equal to the reaction received by the object.
F₁₂ = -F₂₁
m₁a₁ = -m₂a₂
m₁v₁/t = -m₂v₂/t
m₁v₁ = -m₂v₂
m₁v₁ + m₂v₂ = 0
<h3>For an elastic collision involving two objects</h3>
The sum of the initial momentum must be equal to sum of final momentum.
- let initial velocity = u
- let final velocity = v
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
Thus, from Newton’s Third Law, the Law of Conservation of Momentum for an elastic collision is derived as m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂.
Learn more about conservation of linear momentum here: brainly.com/question/7538238
Answer:
(A) Th = 818.6 K
(B) Qh = 14211.7 J
Explanation:
efficiency (n) = 0.537
temperature of cold reservoir (Tc) = 379 K
heat rejected (Qc) = 6580 J
(A) find the temperature of the hot reservoir (Th)
n = 1 -
0.537 = 1 -
= 1 - 0.537 = 0.463
Th =
Th = 818.6 K
(B) what amount of heat is put into the engine (Qh) ?
from
Qh = 6580 ÷
Qh = 14211.7 J
Answer for 1 is d
answer for s is also d