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3 years ago

How many of the following are compounds? H2O, N2O4, NaOH, MnO2, HF

2 answers:

7 0

Element= all of the same type of substance
Compound= different substances chemically bonded
Mixture= different substances not chemically bonded

so they are all compounds

lukranit [14]3 years ago

4 0

Im pretty sure all of them are compounds

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*<br> What is the volume, in liters, of 12.0 kg of H2 at STP?

neonofarm [45]

Answer:

According to Avogadro's law, the volume of one mole of any gas at Standard Temperature and Pressure (STP = 273 K and 1 atm) is 22.4 L. Two important Gas Laws are required in order to convert the experimentally determined volume of hydrogen gas to that at STP. 1.

Explanation:

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3 years ago

A 5g piece of aluminum foil (c=0.897) at 100°C is dropped into a 25g container of water (c=4.184) at 20°C. What is the final tem

jeyben [28]

Answer:

23.6°C

Explanation:

use delta h method

5 0

3 years ago

Please help asap loll

BlackZzzverrR [31]

Explanation:

Metals -

Left side of periodic table
Malleable
Ductile
Good conductor
Mostly solid
Shinly lusture

Non-metals -

Poor conductor
Dull
Brittle
Right side of periodic table

Metalloids -

Properties of metals and non-metals.
Found on the 'staircase' of the periodic table.

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3 years ago

Relating ideas explain why ionic crystals melt at much higher temperatures than typical covalent molecular crystals.

gayaneshka [121]

Because of the way the temp is set up

6 0

3 years ago

How many moles in 2.21 x10E24 atoms of aluminum

lisov135 [29]

<h3>Answer:</h3>

3.67 mol Al

<h3>General Formulas and Concepts:</h3>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

2.21 × 10²⁴ atoms Al

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

Set up: $\displaystyle 2.21 \cdot 10^{24} \ atoms \ Al(\frac{1 \ mol \ Al}{6.022 \cdot 10^{23} \ atoms \ Al})$
Divide: $\displaystyle 3.66988 \ mol \ Al$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

3.66988 mol Al ≈ 3.67 mol Al

7 0

3 years ago