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nirvana33 [79]
4 years ago
7

A small ball with mass 2.50 kg is mounted on one end of a rod 0.750 m long and of negligible mass. The system rotates in a horiz

ontal circle about the other end of the rod at 4900 rev/min.
Physics
1 answer:
alina1380 [7]4 years ago
3 0

Answer:

1.40625 kg-m^2

Explanation:

Supposing we have to calculate rotational moment of inertia

Given:

Mass of the ball m= 2.50 kg

Length of the rod, L= 0.78 m

The system rotates in a horizontal circle about the other end of the rod

The constant angular velocity of the system, ω= 5010 rev/min

The rotational inertia of system is equal to rotational inertia of the the ball about other end of the rod because the rod is mass-less

I_{sys}= mL^2= 2.50\times 0.75^2

=1.40625 kg-m^2

m= mass of the ball and L= length of the ball

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The correct answer is: 
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While driving on the highway, you have a tire blowout. after you have slowed down and regained control, you should?
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4 years ago
Water is circulating through a closed system of pipes in a two floor apartment. On the first floor, the water has a gauge pressu
anastassius [24]

Answer:

The value of gauge pressure at outlet = -38557.224 pascal

Explanation:

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\frac{P_{1}}{9810} + \frac{V_{1} ^{2}}{19.62} + h_{1} = \frac{P_{2}}{9810} + \frac{V_{2} ^{2}}{19.62} + h_{2} --------------(1)

Where

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V_{1} = velocity at inlet =  2.4 \frac{m}{sec}

P_{2} = Gauge pressure at outlet = we have to calculate

V_{2} = velocity at outlet = 3.5 \frac{m}{sec}

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Put all the values in equation (1) we get,

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⇒ \frac{P_{2}}{9810} = - 3.9304

⇒ P_{2} = - 38557.224 pascal

This is the value of gauge pressure at outlet.

3 0
3 years ago
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Answer:

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