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Alex73 [517]
3 years ago
13

Think about agriculture research which of the following statements is accurate?

Chemistry
1 answer:
irina [24]3 years ago
4 0

A.genetic modification of food helps it grow more easily in certain areas

Explanation:

The statement genetic modification of food helps it grow more easily in certain areas is a form of agricultural research that is very accurate.

Genetically modifying food is common practice in order to encourage desirable and sustainable traits in plant species.

  • Drought resistant breeds can tolerate a much lower level of water in some specific areas.
  • Disease resistant breeds are more adapted to outbreaks of plant epidemics.
  • Overall, genetic modification of food helps them to grow and produce better.

learn more:

Genetic recombination brainly.com/question/12685192

#learnwithBrainly

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If 6.02*10^23 molecules of ammonia react with 12.04*10^23 molecules of hydrogen chloride, how many molecules are in the reaction
Helen [10]

Answer:

18.06 × 10²³ molecules

Explanation:

Add the two amounts of molecules together.

6.02 × 10²³  +  12.04 × 10²³  =  18.06 × 10²³

You will have 18.06 × 10²³ molecules in the vessel when the reaction is complete.  This is because of the Law of Conservation of Mass.  Mass is neither created nor destroyed in chemical reactions.  You will have the exact number of molecules in the reaction vessel as you did in the beginning.  The types of molecules may change, but the number will stay the same.

3 0
3 years ago
How many sodium ions are present in 325 ml of 0.850 m na2so4?
NISA [10]

Answer:

Na^+_{ions}=3.33x10^{23}Na^+_{ions}

Explanation:

Hello,

In this case, for the given molarity and volume of such solution, the moles of sodium sulfate are computed below:

n_{Na_2SO_4}=0.850\frac{mol}{L}*0.325L=0.276molNa_2SO_4

Now, by using the Avogadro's number, the ions result:

Na^+_{ions}=0.276molNa_2SO_4*\frac{2molNa^+}{1molNa_2SO_4} *\frac{6.022x10^{23}Na^+_{ions}}{1molNa^+} \\\\Na^+_{ions}=3.33x10^{23}Na^+_{ions}

Best regards.

4 0
3 years ago
what is the molarity of a solution prepared by dissolving 1.25g of HCL gas into enough water to make 30cm cube of solution?
Tpy6a [65]
Molars are cavities in your teeth the dentists will scrape them out and fill them in for you at your earliest convinence need help with anything else while im here i can assist you!
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3 years ago
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3 years ago
Assuming equal concentrations and complete dissociation, rank these aqueous solutions by their freezing points. nh4cl cobr3 k2so
Illusion [34]
Answer: CoBr3 < K2SO4 < NH4 Cl

Justification:

1) The depression of the freezing point of a solution is a colligative property, which means that it depends on the number of particles of solute dissolved.

2) The formula for the depression of freezing point is:

ΔTf = i * Kf * m

Where i is the van't Hoof factor which accounts for the dissociation of the solute.

Kf is the freezing molal constant and only depends on the solvent

m is the molality (molal concentration).

3) Since, you are assuming equal concentrations and complete dissociation of the given solutes, the solute with more ions in the molecular formula will result  in the solution with higher depression of the freezing point (lower freezing point).

4) These are the dissociations of the given solutes:

a) NH4 Cl (s) --> NH4(+)(aq) + Cl(-) (aq) => 1 mol --> 2 moles

b) Co Br3 (s) --> Co(3+) (aq) + 3Br(-)(aq) => 1 mol --> 4 moles

c) K2SO4 (s) --> 2K(+) (aq) + SO4 (2-) (aq) => 1 mol --> 3 moles

5) So, the rank of solutions by their freezing points is:

CoBr3 < K2SO4 < NH4 Cl
4 0
3 years ago
Read 2 more answers
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