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3 years ago

What does it mean for a reaction to be endothermic? choose 2 of the following

Physics

2 answers:

trapecia [35]3 years ago

5 0

Answer:

A. to stop the reaction and C. to warm up reaction

Explanation: birb

Rainbow [258]3 years ago

3 0

Answer: I would choose options C and D

Explanation:

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Two forces act on a 6.00-kg object. One of the forces is 10.0 N. If the object accelerates at 2.00 m/s2

liubo4ka [24]

Given :

Two forces act on a 6.00-kg object. One of the forces is 10.0 N.

Acceleration of object 2 m/s².

To Find :

The greatest possible magnitude of the other force.\

Solution :

Let, other force is f.

So, net force, F = 10 + f.

Now, acceleration is given by :

$a=\dfrac{F}{mass}\\\\a= \dfrac{10+f}{6}\\\\\dfrac{10+f}{6}=2\\\\f = 12 - 10\\\\f = 2 \ N$

Therefore, the greatest possible magnitude of the other force is 2 N.

Hence, this is the required solution.

7 0

3 years ago

A ball is dropped from the top of a building.After 2 seconds, it’s velocity is measured to be 19.6 m/s. Calculate the accelerati

zlopas [31]

Answer:

acceleration, a = 9.8 m/s²

Explanation:

'A ball is dropped from the top of a building' indicates that the initial velocity of the ball is zero.

u = 0 m/s

After 2 seconds, velocity of the ball is 19.6 m/s.

t = 2s, v = 19.6 m/s

Using

v = u + at

19.6 = 0 + 2a

a = 9.8 m/s²

6 0

4 years ago

Read 2 more answers

What happens when electrical devices are added to the circuit ?

Ksivusya [100]

Answer:

they get power.

Explanation:

7 0

3 years ago

PLEASE I NEED HELP!!

Bond [772]

Answer:

may be 5 m is the answer of this question

4 0

2 years ago

An RC car is carrying a tiny slingshot with a spring constant of 85 N/m at 0.2 m off the ground at 5.6 m/s. The sling shot is pu

ololo11 [35]

Answer:

The velocity of the steel pellet relative to the ground when it leaves the sling shot is approximately 5.960 meters per second.

Explanation:

Let suppose that RC car-slingshot-steelpellet is a conservative system, that is, that non-conservative forces (i.e. friction, air viscosity) can be neglected. The velocity of the steel pellet can be found by means of the Principle of Energy Conservation and under the consideration that change in gravitational potential energy is negligible and that the RC car travels at constant velocity:

$\frac{1}{2}\cdot (m_{C}+m_{P})\cdot v_{o}^{2} + \frac{1}{2}\cdot k\cdot x^{2} = \frac{1}{2}\cdot m_{C}\cdot v_{o}^{2} + \frac{1}{2}\cdot m_{P}\cdot v^{2}$

$\frac{1}{2}\cdot m_{P}\cdot v_{o}^{2} + \frac{1}{2}\cdot k\cdot x^{2} = \frac{1}{2}\cdot m_{P}\cdot v^{2}$

$m_{P}\cdot v_{o}^{2} + k\cdot x^{2} = m_{P}\cdot v^{2}$

$v^{2} = v_{o}^{2} + \frac{k}{m_{P}}\cdot x^{2}$

$v = \sqrt{v_{o}^{2}+\frac{k}{m_{P}}\cdot x^{2} }$ (1)

Where:

$v_{o}$ - Initial velocity of the steel pellet, measured in meters per second.

$v$ - Final velocity of the steel pellet, measured in meters per second.

$k$ - Spring constant, measured in newtons per meter.

$m_{P}$ - Mass of the steel pellet, measured in kilograms.

$m_{C}$ - Mass of the RC car, measured in kilograms.

$x$ - Initial deformation of the spring, measured in meters.

If we know that $v_{o} = 5.6\,\frac{m}{s}$ , $k = 85\,\frac{N}{m}$ , $m_{P} = 0.025\,kg$ and $x = 0.035\,m$ , then the velocity of the steel pellet relative to the ground when it leaves the sling shot is:

$v = \sqrt{\left(5.6\,\frac{m}{s} \right)^{2}+\frac{\left(85\,\frac{N}{m} \right)\cdot (0.035\,m)^{2}}{0.025\,kg} }$

$v \approx 5.960\,\frac{m}{s}$

The velocity of the steel pellet relative to the ground when it leaves the sling shot is approximately 5.960 meters per second.

5 0

3 years ago