It is number 3 because I know it is
Answer: work = 1,305kJ
Explanation:
angle= 30°
force= 1,500N
distance= 1,000m
The formula for work is : Work= force x distance, however there is an angle of 30° between the direction of force applied and the direction of motion, therefore force must be decomposed to its value on the horizontal axis which is the direction of motion by using the cosine of the very angle.
W= F×cos(α)×D
W= 1,500×cos (30)×1,000
W= 1,305kJ ( kilojoules)
K.E1=1/2×100×3²
=50×9
=450J
K.E2=1/2×100×36
=50×36
=1800J
Explanation:
Given that,
Frequency of the power line, f = 6 Hz
Value of maximum electric field strength of 11.6 kV/m
(a) The wavelength of this very low frequency electromagnetic wave is given by using relation as :
(b) As its can be seen that the wavelength of this wave is very high. It shows that it is a radio wave.
(c) The relation between the maximum magnetic field strength and maximum electric field strength is given by :
So, the maximum magnetic field strength is 
.
Answer:
v = 23.66 m/s
Explanation:
recall that one of the equations of motion may be expressed:
v² = u² + 2as,
Where
v = final velocity (we are asked to find this)
u = initial velocity = 0 m/s since we are told that it starts from rest
a = acceleration = 0.56m/s²
s = distance traveled = given as 500m
Simply substitute the known values into the equation:
v² = u² + 2as
v² = 0 + 2(0.56)(500)
v² = 560
v = √560
v = 23.66 m/s
