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3 years ago

Chemical manufacturers must present which information on the product's label?

Engineering

1 answer:

Wewaii [24]3 years ago

6 0

Answer:

hazardous chemicals leaving the workplace is labeled, tagged or marked with the following information: product identifier; signal word; hazard statement

Explanation:

this is so you know what chemicals are in it

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The temperature at which the polymer becomes viscous is called: glass transition temperature (Tg). a)-True b)- false?

Contact [7]

Answer:

a)True

Explanation:

The temperature at which the polymer becomes viscous is called glass transition temperature.

When polymer is heated then it will become viscous and temperature is called glass transition temperature.

Glass temperature depends on the chemical structure of the polymer.

Polymer are made of long change structure and these change are connected together one by one and form a complex structure.

Example -Rubber or elastomer,Plastics.

7 0

3 years ago

An array of eight aluminum alloy long fins, each 3 mm wide, 0.4 mm thick, and 40 mm long, is used to cool a transistor. When the

Mashutka [201]

Answer:

0.08704 W

Explanation:

converting the mm to m (1000mm = 1m)

cross-sectional area of the fins, Ac = (0.003) (0.0004) = 0.0000012‬m^2

The wetted perimeter of the cross-section, P = 2 (0.003 + 0.0004) = 0.0068‬m

Thickness of solid in direction of heat flow, B^2 = (heat transient coefficient, h) (The wetted perimeter of the cross-section, P) ÷ (Thermal conductivity, k) (cross-sectional area of the fins, Ac)

B^2 = (8 W/m2K)(0.0068‬m) ÷ (175 W/mK)(0.0000012‬m^2)

=259.0476m^-2

B= square root of the result

B = 16.09m^-1

we now look for:

The Coordinate, x = B, multiplied by Length, L

x = (16.09m^-1) (0.04m) = 0.6436‬

finding the side area of a fin = P multiplied by Length, L

= 0.0068‬m X 0.04m = 0.000272m^2

Neglecting inefficiency, assuming the fins are all 100% efficient, the power they would dissipate =

h, Heat-transfer coefficient (PL) (temperature of at the base - temperature at the ambient air)

= (8) (0.000272m^2)(340 K- 300k)

= 0.08704 W

6 0

3 years ago

Store the amount of the minimum loan in min_loan and the amount of the maximum loan in max_loan Then, store the name of the coun

Tresset [83]

Answer:

See Explanation

Explanation:

The question has missing details;however, I'm able to pick the following points from the question

There's supposed to be a list of loan amounts
There's also supposed to be a list of countries that took loans. This list will correspond to the loan list

Having said that, the question can be solved in two ways.

I prompt the user to enter loan amounts and corresponding country
I assume any value for the loan amounts and the country

I'll answer this question using the first method and the solution is as follows (See Comments for line by line explanation):

#This line prompt user for number of countries

n = int(input("Number of countries: "))

#This initializes an empty list for loan amounts

loan_amounts = []

#This initializes an empty list for country

country = []

#The following iteration gets names of countries and their respective loan amounts

for i in range(0,n):

country_name = input("Name of country: ")

loan = int(input("Loan Amount: "))

country.append(country_name)

loan_amounts.append(loan)

#This gets the maximum loan

max_loan = max(loan_amounts)

#This gets the index of the maximum loan

iindex = loan_amounts.index(max_loan)

#This gets the country with the maximum loan

max_country = country[iindex]

#This gets the minimum loan

min_loan = min(loan_amounts)

#This gets the index of the minimum loan

iindex = loan_amounts.index(min_loan)

#This gets the country with the minimum loan

min_country = country[iindex]

#This prints the country with the maximum loan and the loan amount

print(str(max_country)+": "+str(max_loan))

#This prints the country with the minimum loan and the loan amount

print(str(min_country)+": "+str(min_loan))

3 0

3 years ago

The charge entering the positive terminal of an element is q = 5 sin 4 π t mC while the voltage across the element (plus to minu

polet [3.4K]

Answer:

a)123.37 mW

b) 58.75 mJ

Explanation:

a) The current (i) flowing through the terminal is given as:

$i=\frac{dq}{dt} \\i=\frac{d(5sin(4\pi t)}{dt} =20\pi cos(4\pi t)\ mA\\$

The Power delivered to the element (P(t)) is given as:

$P(t)=v(t)i(t)= 3 cos(4\pi t)*20\pi cos(4\pi t)*10^{-3}\\P(t)=60\pi cos^2(4\pi t)*10^{-3}\\at \ t \ =\ 0.3s,\ the \ power\ delivered\ is:\\P(0.3) = 60\pi cos^2(4\pi *0.3)*10^{-3}=123.37mW$

b) the energy delivered to the element (W) between 0 and 0.6 s is given as:

$W = \int\limits^0_{0.6} {P(t)} \, dt \\W=\int\limits^0_{0.6} {60\pi cos^{2}(4\pi t)} \, dt =58.75mJ$

6 0

3 years ago

Explain the difference, on the basis of the test results, between the ultimate strength and the "true" stress at fracture.

gayaneshka [121]

Answer / Explanation:

On the basis of the test result, Ultimate strength which is mostly known as the ultimate tensile strength is the strength attached to the ability or capacity of a structural element or material used in the test to withstand elongation forces or pull force applied to it.

WHILE,

True stress at fracture can be classified as stress or load associated to the point where yielding or fracture occurred divided by the cross-sectional area at the yield point.

5 0

3 years ago