Answer:

Explanation:
<u>Projectile Motion</u>
In projectile motion, there are two separate components of the acceleration, velocity and displacement. The horizontal component has zero acceleration (assuming no friction), and the acceleration in the vertical direction is always the acceleration of gravity. The basic formulas are shown below:

Where
is the angle of launch respect to the positive horizontal direction and Vo is the initial speed.

The horizontal and vertical distances are, respectively:


The total flight time can be found as that when y = 0, i.e. when the object comes back to ground (or launch) level. From the above equation we find

Using this time in the horizontal distance, we find the Range or maximum horizontal distance:

Let's solve for 

This is the general expression to determine the angles at which the projectile can be launched to hit the target. Recall the angle can have to values for fixed positive values of its sine:


Or equivalently:

Given Vo=37 m/s and R=70 m


And

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Answer:
W = 31.393 Btu
Explanation:
given data
piston-cylinder assembly contains water = 0.5 lb
p1 = 40 lbf/in² = 40 × 144 lbf/ft²
T1 = 300° F
p2 = 14.7 lbf/in² = 14.7 × 144 lbf/ft²
pv 1.2 = constant.
solution
we use here superheated table A 4E to get value for p1 = 40 and t = 300
v1 = 11.04 ft³/lbm
so we know
,...............1
solve it we get
v2 = 25.425 ft³/lbm
and here
W =
...............2
put here value we get
W =
solve it we get
W = 31.393 Btu
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