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3 years ago

Thirty- eight percent of the animals in a dog and cat rescue center are cats. What percentage are dogs?

Mathematics

1 answer:

lesya [120]3 years ago

5 0

Answer:

62%

Step-by-step explanation:

100-38=62

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. A mason has 7,758 bricks that he needs to share equally among 9 different building sites. How many

sergij07 [2.7K]

Why does he have bricks .

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3 years ago

Read 2 more answers

The number of cars running a red light in a day, at a given intersection, possesses a distribution with a mean of 2.4 cars and a

liberstina [14]

Answer:

The sampling distribution of the sample mean is:

$\bar X\sim N(\mu_{\bar x}=2.4,\ \sigma_{\bar x}=0.40)$

Step-by-step explanation:

According to the Central Limit Theorem if we have a population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

Then, the mean of the distribution of sample means is given by,

$\mu_{\bar x}=\mu$

And the standard deviation of the distribution of sample means is given by,

$\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}$

Let X = number of cars running a red light in a day, at a given intersection.

The information provided is:

$E(X)=\mu=2.4\\SD(X)=\sigma=4\\n=100$

The sample selected is quite large, i.e. n = 100 > 30.

The Central limit theorem can be used to approximate the sampling distribution of the sample mean number of cars running a red light in a day, by the Normal distribution.

The mean of the sampling distribution of the sample mean is:

$\mu_{\bar x}=\mu=2.4$

The standard deviation of the sampling distribution of the sample mean is:

$\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{4}{\sqrt{100}}=0.40$

The sampling distribution of the sample mean is:

$\bar X\sim N(\mu_{\bar x}=2.4,\ \sigma_{\bar x}=0.40)$

8 0

3 years ago

The units of the subway map below are in miles. Suppose the routes between stations are straight, find the distance you would tr

Nat2105 [25]

Answer:

4.5 miles

Step-by-step explanation:

On the graph,

Elm station is located at (-3,-6)
Oak station is located at (-1,-2)

We use the distance formula to find the distance between Elm and Oak.

$\text{Distance Formula=}\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\(x_1,y_1)=(-3,-6), (x_2,y_2)=(-1,-2)\\Distance=\sqrt{(-1-(-3))^2+((-2)-(-6))^2} \\=\sqrt{(-1+3)^2+(-2+6)^2} \\=\sqrt{2^2+4^2}\\=\sqrt{20}$ Units \\ Distance =4.5 mile (to the nearest tenth of a mile.)$