CH3CH2NHCH3 is a weak base.
Answer:
40.34 g
Explanation:
First, we divide the heat to release by the heat of combustion to obtain the required moles of compound:
541.20 kJ/(1160.00 kJ/mol) = 0.4665 mol
So, we have to burn approximately 0.47 mol of the compound. We convert the moles to mass in grams by using the molar mass:
mass = molar mass x moles = 86.47 g/mol x 0.4665 mol = 40.34 g
Therefore, you must burn 40.34 grams of the compound to release 541.20 kJ of heat.
Use the formula:
P1V1/T1N1 = P2V2/T2N2
You can cross out T1,N1,T2, and N2 because you are working with pressure and volume in this equation.
Now, you are left with Boyle’s Law:
P1V1 = P2V2
Substitute the values in
STP = 1 atm for pressure
(1 atm)(2.1L) = P2 (0.125 L) [I converted 125 ml to liters so they would be the same unit]
Now, divide both sides by 0.125 to find P2
P2 = (1 atm)(2.1 L)/(0.125 L)
Liters cancel out
P2 = 16.8 atm
There are 20.8 moles of propanol
<h3>Further explanation </h3>
The mole is the number of particles(molecules, atoms, ions) contained in a substance
1 mol = 6.02.10²³ particles
Can be formulated
N=n x No
N = number of particles
n = mol
No = Avogadro's = 6.02.10²³
1.2 x 10⁵ molecules of propanol
