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Dmitry [639]
4 years ago
13

A. B. C. D. -___________

Physics
1 answer:
mixas84 [53]4 years ago
6 0
Where is the data for this question? what is the purpose ?
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Which is a characteristic of thermal energy transfer through convection
Lynna [10]

Answer:  The thermal energy transfer is When a fluid, such as air or a liquid, is heated and then travels away from the source, it carries the thermal energy along.

Explanation: heat transfer is called convection.  hopefully this was helpful.

6 0
3 years ago
Reducing, reusing, and recycling in your office is likely to _______.
iris [78.8K]
Conserve natural resources, energy and landfill space.
4 0
4 years ago
Anna drives north at a speed of 50 km/h for the first hour. Then, she drives north for a second hour but slows down to 30 km/h.
8090 [49]

Answer:

The correct answer is A The distance is greater in the first hour because her speed is faster.

Explanation:

During the first hour, Anna is driving at a speed of 50 km/h. During the second hour, she is only driving at a speed of 30 km/h. The faster she goes, the farther she will go.

Hope this helps,

♥<em>A.W.E.</em><u><em>S.W.A.N.</em></u>♥

8 0
3 years ago
Read 2 more answers
A shot-putter accelerates a 7.2 kg shot from rest to 17 m/s . what work did the shot-putter do on the ball?
garri49 [273]
<span>1.0x10^3 Joules The kinetic energy a body has is expressed as the equation E = 0.5 M V^2 where E = Energy M = Mass V = Velocity Since the shot was at rest, the initial energy is 0. Let's calculate the energy that the shot has while in motion E = 0.5 * 7.2 kg * (17 m/s)^2 E = 3.6 kg * 289 m^2/s^2 E = 1040.4 kg*m^2/s^2 E = 1040.4 J So the work performed on the shot was 1040.4 Joules. Rounding the result to 2 significant figures gives 1.0x10^3 Joules</span>
6 0
4 years ago
The angular speed of the hour hand of a clock, in rad/min, is:___________
lapo4ka [179]

The angular speed is defined as:

<h2>                                      ω=\frac{2\pi}{T}</h2>

        where

                                     T=12*60=720min

                                     \omega=\frac{2\pi}{720}

                                     \omega=4.4**10^{-3} rad/min

4 0
3 years ago
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