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Dmitry [639]
3 years ago
13

A. B. C. D. -___________

Physics
1 answer:
mixas84 [53]3 years ago
6 0
Where is the data for this question? what is the purpose ?
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If an object is moving up, is it considered to have a positive or negative velocity?
grin007 [14]

Answer:

A positive velocity

Explanation:

7 0
3 years ago
What kind of surface is suitable for infared radiation
nlexa [21]

Answer:

Different surfaces

<h3>You can see that dull surfaces are good absorbers and emitters of infrared radiation. Shiny surfaces are poor absorbers and emitters (but they are good reflectors of infrared radiation</h3>
8 0
3 years ago
List down all the jovian planets in order of increasing distance from the sun
Olenka [21]

Answer:

There are total eight planets in the solar system and the average distance from the sun to each planet in increasing order is given below.

Explanation:

The average distance from the sun is listed below in increasing order.

1. Mercury  - It is the most closet planet to Sun, 57 million km

2. Venus  - 108 million km

3. Earth  - 150 million km

4. Mars  - 228 million km

5. Jupiter  - 779 million km

6. Saturn  - 1.43 billion km

7. Uranus  - 2.88 billion km

8. Neptun - It is the most farthest from the Sun, 4.50 billion km

8 0
3 years ago
The driver of a car traveling at 22.8 m/s applies the brakes and undergoes a constant deceleration of 2.95 m/s 2 . How many revo
a_sh-v [17]

Answer:

70 revolutions

Explanation:

We can start by the time it takes for the driver to come from 22.8m/s to full rest:

t = \Delta v/a = (22.8 - 0)/2.95 = 7.73 s

The tire angular velocity before stopping is:

\omega_0 = v/r = 22.8 / 0.2 = 114 rad/s

Also its angular decceleration:

\alpha = a / r = 2.95/0.2 = 14.75 rad/s^2

Using the following equation motion we can findout the angle it makes during the deceleration:

\omega^2 - \omega_0^2 = 2\alpha\Delta \theta

where \omega = 0 m/s is the final angular velocity of the car when it stops, \omega_0 = 114rad/s is the initial angular velocity of the car \alpha = 14.75 rad/s2 is the deceleration of the can, and \Delta \theta is the angular distance traveled, which we care looking for:

-114^2 = 2*(-14.75)*\Delta \theta

\Delta \theta = 440rad or 440/2π = 70 revelutions

4 0
3 years ago
Calculate the total resistance in a series circuit made up of resistances of 3Ω, 4Ω, and 5Ω.
-BARSIC- [3]
The total resistance in a series circuit is equal to the sum of all resistors (R total = ΣRi).

R total = R1 + R2 + R3 = (3 + 4 + 5) Ω = 12 Ω
5 0
3 years ago
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