Answer:
3.6 N
Explanation:
The magnitude of centripetal force in this case is equal to the magnitude of tension in the spring.
The formula is :
T= mv²/r ------where T is tension
m= mass of object =0.8 kg
v= velocity of object {tangential velocity} = 3.0 m/s
r= length of string = 2m
Applying the formula with real values;
T= mv²/r
T= {0.8 * 3²} / 2
T= { 7.2}/2 = 3.6 N
By applying the second equation of motion, the speed at which he threw the second stone is equal to 12.10 m/s.
<h3>How to determine the speed?</h3>
First of all, we would calculate the time taken by the first stone to reach a height of 49 meters by applying the second equation of motion as follows:
S = ut + ½gt²
49 = 0(t) + ½ × 9.8 × t²
49 = 4.9t²
t² = 49/4.9
t = √10
t = 3.16 seconds.
Now, we can determine the speed at which he threw the second stone:
<u>Note:</u> Time = 3.16 - 1 = 2.16 seconds.
S = ut + ½gt²
49 = u(2.16) + ½ × 9.8 × 2.16²
49 = 2.16u + 22.86
2.16u = 49 - 22.86
u = 26.14/2.16
u = 12.10 m/s.
Read more on initial speed here: brainly.com/question/19365526
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Answer:
1000 kg
Explanation:
We know the formula for finding out weight is W=mg
W= 10,000 N
M=?
g=10 N/KG
W=mg
10,000=10m
m=1000kg
Gravity is often assumed to be the same everywhere on Earth, but it varies because the planet is not perfectly spherical or uniformly dense. In addition, gravity is weaker at the equator due to centrifugal forces produced by the planet's rotation
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