The water side of the wall of a 60-m-long dam is a quarter-circle with a radius of 7 m. Determine the hydrostatic force on the d
am and its line of action when the dam is filled to the rim. Take the density of water to be 1000 kg/m3.
1 answer:
Answer:


Explanation:
r = Radius of circle = 7 m
w = Width of dam = 60 m
h = Height of the dam will be half the radius = 
A = Area = 
V = Volume = 
Horizontal force is given by

Vertical force is given by

Resultant force is

The hydrostatic force on the dam is
.
The direction is given by

The line of action is
.
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Answer:
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PV= nRT
Pressure is constant
P* (change in volume) = nR* (change in temperature)
S ?
U 0m/s
V ?
A 0.1m/s^2
T 2min (120 sec)
S=ut+0.5at^2
S=0(120 sec)+0.5(0.1m/s^2)(120 sec)^2
S=720m
Distance double 720m*2=1440m
V^2=u^2+2as
V^2=(0)^2+2(0.1 m/s^2)(1440m)
V^2=288
V= square root of 288=12 root 2=16.97 to 2 decimal places
Voltage = current(I) * resistance (R)
V = 18
R = 6
18 = I * 6
I = 18/6 = 3 Amps or D
Answer:
66w
Explanation:
p=w/t
p=660/10
p=66
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