Question

How many grams of NaCl is present in .75 L of a 1 M solution of NaCl?

Answer 1

Answer:

The answer to your question is 43.9 g of NaCl

Explanation:

Data

Grams of NaCl = ?

Volume = 0.75 L

Molarity = 1 M

Number of moles = ?

Formula

$Molarity = \frac{number of moles}{volume}$

Solve for number of moles

Number of moles = Molarity x volume

Substitution

Number of moles = 1 x 0.75

                             = 0.75

Molecular weight of NaCl = 23 + 35.5 = 58.5

Calculate the grams of NaCl using proportions

                           58.5 g of NaCl ---------------- 1 mol

                              x                     ---------------- 0.75 moles

                              x = (0.75 x 58.5) / 1

                              x = 43.9 g of NaCl